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jonny [76]
3 years ago
10

What would you do to solve the system?

Mathematics
1 answer:
kipiarov [429]3 years ago
6 0
Answer:

Explanation:

12x = 48 - 8y
10x + 8y = 38
———————
12x + 8y = 48
10x + 8y = 38
———————
12x + 8y = 48
-1(10x + 8y = 38)
————————
12x + 8y = 48
-10x - 8y = -38
————————
2x = 10
x = 10/2 = 5

If x = 5 then:
10x + 8y = 38
10(5) + 8y = 38
50 + 8y = 38
8y = 38 - 50
8y = -12
y = -12/8
y = -3/2

Therefore, x = 5 and y = -3/2

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Three consecutive even integers have a sum of 18. find the integers ​
natta225 [31]

Answer:

5,6,7

Step-by-step explanation:

x-1+x+x+1=18

3x=18

x=6

5,6,7

5 0
3 years ago
PLEASE HELP                                                                                                                    
sweet [91]
To model and solve our situation we are going to use the equation: s= \frac{d}{t}
where
s is speed
d is distance 
t is time 

1. We know that the distance between the cities is 2400 miles, so d=2400. We also know that the speed of the plane is 450 mi/h. Since we don't know the speed of the air, S_{a}=?. We don't know how much the westward trip takes, so t_{w}=?, and we also don't know how much the eastward trip takes, so t_{e}=?.

Going westward. Here the plane is flying against the air, so we need to subtract the speed of the air from the speed of the plane:
450-S_{a}= \frac{2400}{t_{w} }
Going eastward. Here the plane is flying with the the air, so we need to add the speed of the air to the speed of the plane:
450+S_{a}= \frac{2400}{t_{e} }

2. We know for our problem that the round trip takes 11 hours; so the total time of the trip is 11, t_{t}=11. Notice that we also know that the total time of the trip equals time of the tip going westward plus time of the trip going eastward, so t_{t}=t_{w}+t_{e}. Since we know that the total trip takes 11 hours, we can replace that value in our total time equation and solve for t_{w}:
11=t_{w}+t_{e}
t_{w}=11-t_{e}

Now we can replace t_{w} in our going westward equation to model our round trip with a system of equations:
450-S_{a}= \frac{2400}{t_{w}}
450-S_{a}= \frac{2400}{11-t_{e} } equation (1)
450+S_{a}= \frac{2400}{t_{e}} equation (2)

3. To solve our system of equations, we are going to solve for t_{e} in equations (1) (2):

From equation (1)
450-S_{a}= \frac{2400}{11-t_{e} }
11-t_{e}= \frac{2400}{450-S_{a} }
-t_{e}= \frac{2400}{450-S_{a} } -11
t_{e}=11- \frac{2400}{450-S_{a} }
t_{e}= \frac{4950-11S_{a} -2400}{450-S_{a} }
t_{e}= \frac{2550-11S_{a} }{450-S_{a} } equation (3)

From equation (2):
450+S_{a}= \frac{2400}{t_{e} }
t_{e}= \frac{2400}{450+S_{a} } equation (4)

Replacing (4) in (3)
\frac{2400}{450+S_{a}} = \frac{2550-11S_{a}}{450-S_{a} }
Now, we can solve for S_{a} to find the speed of the wind:
2400(450-S_{a})=(450+S_{a})(2550-11S_{a})
1080000-2400S_{a}=1147500-4950S_{a}+2550S_{a}-11(S_{a})^{2}
11(S_{a})^{2}-67500=0
11(S_{a})^{2}=67500
(S_{a})^{2}= \frac{67500}{11}
S_{a}=+/-  \sqrt{ \frac{67500}{11} }
Since speed cannot be negative, the solution of our equation is:
S_{a}= \sqrt{ \frac{67500}{11} }
S_{a}=78.33

We can conclude that the speed of the wind is 78 mph.

3 0
4 years ago
Use the disruptive property to simplify (-5-c)(-1)<br> A-5 -c <br> B 5+c<br> C -5+c <br> D 5-c
Nady [450]

Answer:

B). 5+c

Step-by-step explanation:

we need to distribute -5-c to -1

we can do it as its written or we can flip it around and still get the same answer. When we distribute we multiply the varable or number out parenthesis with the ones in the paretesis  

so -5 *-1=5

-c*-1=c

these two are positive now so they are no longer being subtracted from each other...

your answer is

B). 5+c

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What is the slope of a line that is perpendicular to the line represented by the equation y-5x=5?
zalisa [80]
Perpendicular lines have negative reciprocal slop to each other.
So first solve for y.
Slope will be the coefficient of x in y=mx+c form.
m is the slope. Then negative reciprocal this slope and in this case the answer is -1/5
6 0
3 years ago
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Jobisdone [24]

Answer:

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3 0
3 years ago
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