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jonny [76]
3 years ago
10

What would you do to solve the system?

Mathematics
1 answer:
kipiarov [429]3 years ago
6 0
Answer:

Explanation:

12x = 48 - 8y
10x + 8y = 38
———————
12x + 8y = 48
10x + 8y = 38
———————
12x + 8y = 48
-1(10x + 8y = 38)
————————
12x + 8y = 48
-10x - 8y = -38
————————
2x = 10
x = 10/2 = 5

If x = 5 then:
10x + 8y = 38
10(5) + 8y = 38
50 + 8y = 38
8y = 38 - 50
8y = -12
y = -12/8
y = -3/2

Therefore, x = 5 and y = -3/2

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Assume that females have pulse rates that are normally distributed with a mean of μ=73.0 beats per minute and a standard deviati
Gennadij [26K]

Answer:

a. the probability that her pulse rate is less than 76 beats per minute is 0.5948

b. If 25 adult females are randomly​ selected,  the probability that they have pulse rates with a mean less than 76 beats per minute is 0.8849

c.   D. Since the original population has a normal​ distribution, the distribution of sample means is a normal distribution for any sample size.

Step-by-step explanation:

Given that:

Mean μ =73.0

Standard deviation σ =12.5

a. If 1 adult female is randomly​ selected, find the probability that her pulse rate is less than 76 beats per minute.

Let X represent the random variable that is normally distributed with a mean of 73.0 beats per minute and a standard deviation of 12.5 beats per minute.

Then : X \sim N ( μ = 73.0 , σ = 12.5)

The probability that her pulse rate is less than 76 beats per minute can be computed as:

P(X < 76) = P(\dfrac{X-\mu}{\sigma}< \dfrac{X-\mu}{\sigma})

P(X < 76) = P(\dfrac{76-\mu}{\sigma}< \dfrac{76-73}{12.5})

P(X < 76) = P(Z< \dfrac{3}{12.5})

P(X < 76) = P(Z< 0.24)

From the standard normal distribution tables,

P(X < 76) = 0.5948

Therefore , the probability that her pulse rate is less than 76 beats per minute is 0.5948

b.  If 25 adult females are randomly​ selected, find the probability that they have pulse rates with a mean less than 76 beats per minute.

now; we have a sample size n = 25

The probability can now be calculated as follows:

P(\overline X < 76) = P(\dfrac{\overline X-\mu}{\dfrac{\sigma}{\sqrt{n}}}< \dfrac{ \overline X-\mu}{\dfrac{\sigma}{\sqrt{n}}})

P( \overline X < 76) = P(\dfrac{76-\mu}{\dfrac{\sigma}{\sqrt{n}}}< \dfrac{76-73}{\dfrac{12.5}{\sqrt{25}}})

P( \overline X < 76) = P(Z< \dfrac{3}{\dfrac{12.5}{5}})

P( \overline X < 76) = P(Z< 1.2)

From the standard normal distribution tables,

P(\overline X < 76) = 0.8849

c. Why can the normal distribution be used in part​ (b), even though the sample size does not exceed​ 30?

In order to determine the probability in part (b);  the  normal distribution is perfect to be used here even when the sample size does not exceed 30.

Therefore option D is correct.

Since the original population has a normal distribution, the distribution of sample means is a normal distribution for any sample size.

5 0
3 years ago
An equilateral triangle has a perimeter of 48 centimeters. If the triangle is dilated by a factor of 0.75, what is the length of
elena55 [62]
The length of each side is 28 cm. 
the perimeter of the equilateral triangle is 48 cm. To find each side of the original triangle, you do 48/3=16cm. since the triangle dilate by 0.75, then you can just do 0.75*16=12cm. then you have to add 12 to 16 because the triangle gets bigger by 12 cm. so 16+12=28 cm.
4 0
3 years ago
If you bought your car 5 years ago for $15,000 and today you can sell for $7000, what was it's rate of depreciation? Round to tw
serg [7]

Answer : The rate of depreciation is, $16000

Step-by-step explanation :

Formula used to calculate the rate of depreciation is:

\text{Depreciation rate}=\frac{\text{Purchase price of asset }+\text{ Salvage value}}{\text{Estimate life of asset}}

Given:

Purchase price of asset = $15000

Salvage value = $7000

Estimate life asset = 3 years

Now put all the given values in the above formula, we get:

\text{Depreciation rate}=\frac{15000+7000}{5}

Deprecation rate = $16000

Therefore, the rate of depreciation is, $16000

5 0
3 years ago
Shawnee is putting $3,500 into an account earning 4.85% interest compounded quarterly. She estimates that it will take just over
Murljashka [212]
A=3,500×(1+0.0485÷4)^(4×11)
A=5,947.99

6000=3500(1+0.0485/4)^4t
Solve for t to know the time needed to reach 6000
Time=11.2
So the time needed is 11 years and 2 months
8 0
3 years ago
Read 2 more answers
A skier is trying to decide whether or not to buy a season ski pass. a daily pass is $75. A season ski pass is $350. The skier w
pishuonlain [190]
Since the skier has to rent skis for 30 dollars per day with both passes, we can ignore it while solving the question.

A season pass is 350, while a daily pass is 75.

\frac{350}{75} = \frac{25\times 14}{25\times 3} = \frac{14}{3} = 4 \frac{2}{3}

So a seasonal pass is equivalent to having 4.6667 daily passes. And you can't buy 0.6667 of a pass.

So, if you went at least 5 days with a seasonal pass, then the seasonal pass would be less expensive than a daily pass.
6 0
3 years ago
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