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3 years ago

9

It's simplifying radicals. the problem is I thought I knew how to do this and turns out I don't. If anyone would be wiling to le

nd a hand. That would be much appreciated.

1 answer:

dmitriy555 [2]3 years ago

4 0

Here is a image of his contact options.

here is a video too.

https://youtu.be/zfmNx_sC82A

I hope this helps.

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the metro train costs $6.30 round trip to ride to work each day. you work 4 days a week (16 days a month). if you can get a mont

Arlecino [84]

The first step is finding how much the metro cost to ride monthly since its a monthly pass. If she rides 16 times for 6.30 every time then you multiply them you should get 100.8. now subtract the original cost before the monthly pass to after. you should get 22.8

3 0

3 years ago

for the data values below construct a 95 confidence interval if the sample mean is known to be 12898 and the standard deviation

Volgvan

Answer:

A 95% confidence interval for the population mean is [3315.13, 22480.87] .

Step-by-step explanation:

We are given that for quality control purposes, we collect a sample of 200 items and find 24 defective items.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample proportion of defective items = 12,898

s = sample standard deviation = 7,719

n = sample size = 5

$\mu$ = population mean

<em> Here for constructing a 95% confidence interval we have used a One-sample t-test statistics as we don't know about population standard deviation. </em>

<u>So, 95% confidence interval for the population mean, </u> $\mu$ <u> is ; </u>

P(-2.776 < $t_4$ < 2.776) = 0.95 {As the critical value of t at 4 degrees of

freedom are -2.776 & 2.776 with P = 2.5%}

P(-2.776 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.776) = 0.95

P( $-2.776 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.776 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.776 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.776 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

<u>95% confidence interval for</u> $\mu$ = [ $\bar X-2.776 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.776 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $12,898-2.776 \times {\frac{7,719}{\sqrt{5} } }$ , $12,898+2.776 \times {\frac{7,719}{\sqrt{5} } }$ ]

= [3315.13, 22480.87]

Therefore, a 95% confidence interval for the population mean is [3315.13, 22480.87] .

5 0

4 years ago

(−4)+(−8)–(−3)+(+6)–(+10)

Setler79 [48]

Answer:

-13

Step-by-step explanation:

-4-8+3+6-10

8 0

4 years ago

Anybody know this..?

lesya [120]

The answer is 5^7 because you add the exponents

3 0

3 years ago

Michael is saving to buy his senior ring. The base cost of the ring is $280 plus any upgrades he wants to purchase. If he saves

Leokris [45]

Answer:

8

Step-by-step explanation:

280/35=x

This is only for the base cost.

You can also right this as:

35(X)=280 and solve for x

35(X)=280

/35 /35

x=8

Hope this helps, good luck!

4 0

3 years ago