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timofeeve [1]
3 years ago
12

Which of the following could be represented by -8?

Mathematics
1 answer:
Llana [10]3 years ago
8 0

Option A: drop of 8 meters would be correct because a drop in this case indicates something has been removed. -8 equals 8 below 0.

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4x-1/2=x+7 WHATS TTHE ANSWER
sesenic [268]

Answer:

x= 5/2 is the answer

5 0
2 years ago
*5 POINTS* plz help i need both of them
yuradex [85]

Answer:

see explanation

Step-by-step explanation:

(a)

(f + g)(x) = f(x) + g(x)

f(x) + g(x) = 6x - 2 + 2x + 4 = 8x + 2

(b)

(f - g)(x) = f(x) - g(x)

f(x) - g(x) = 6x - 2 - (2x + 4) = 6x - 2 - 2x - 4 = 4x - 6

7 0
3 years ago
-5x-3.5 &lt; 6.5<br> -5x &lt;10<br> x &gt;2
Studentka2010 [4]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
a student walks 8 steps east 6 steps northeast 9 steps north west what is her displacement? include magnitude and direction
kati45 [8]

The displacement is 18.03 steps, and the direction is 47.25°

<h3>How to get the displacement?</h3>

We know that displacement is the difference between the final position and the initial position.

We assume the initial position (0, 0). Let's define the positive x-axis as the east and the positive y-axis as the north.

First, the student moves 8 steps east, so she is at:

(0 + 8, 0)

Then she moves 6 steps northeast, so the new position is:

(6*cos(45°) + 8,  6*cos(45°))

Finally, she moves 9 steps due north, so we have:

(6*cos(45°) + 8,  6*cos(45°) + 9)

Then the final position is:

(12.24, 13.24)

So the displacement is:

D = (12.24, 13.24) - (0, 0) =  (12.24, 13.24)

The magnitude of the displacement is:

|D| = \sqrt{12.24^2 + 13.24^2} = 18.03

So the magnitude is 18.03 steps.

And the direction is given by the arctangent of the quotient between the y-component and the x-component:

\theta = Arctg(13.24/12.24) = 47.25 \°

If you want to learn more about displacements:

brainly.com/question/4931057

#SPJ1

8 0
2 years ago
The Cunninghams are moving across the country. Mr. Cunningham leaves 3 hours before Mrs. Cunningham. If he averages 40mph and sh
svp [43]
Recall your d = rt, distance = rate * time

now, if say, by the time they meet, Mr Cunningham has travelled "d" miles, that means Mrs Cunningham must also had travelled "d" miles as well.

However, he left 3 hours earlier, so by the time he travelled "d" miles, and took say "t" hours, for her it took 3 hour less, because she started driving 3 hours later, so, she's been on the road 3 hours less than Mr Cunningham, so by the time they meet, Mrs Cunningham has travelled then "t - 3" hours.

\bf \begin{array}{lccclll}&#10;&\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\&#10;&------&------&------\\&#10;\textit{Mr Cunningham}&d&40&t\\&#10;\textit{Mrs Cunningham}&d&80&t-3&#10;\end{array}&#10;\\\\\\&#10;\begin{cases}&#10;\boxed{d}=40t\\&#10;d=80(t-3)\\&#10;----------\\&#10;\boxed{40t}=80(t-3)&#10;\end{cases}&#10;\\\\\\&#10;\cfrac{40t}{80}=t-3\implies \cfrac{t}{2}=t-3\implies t=2t-6\implies 6=2t-t&#10;\\\\\\&#10;6=t
5 0
3 years ago
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