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REY [17]
3 years ago
7

Does anyone know how to do this

Mathematics
1 answer:
Doss [256]3 years ago
4 0

Answer :Plotting the points into the coordinate plane gives us an observation that this quadrilateral with vertices d(0,0), i(5,5) n(8,4) g(7,1) is a KITE, as shown in figure a.

Step-by-step explanation:

Considering the quadrilateral with vertices

d(0,0)

i(5,5)

n(8,4)

g(7,1)

Plotting the points into the coordinate plane gives us an observation that this quadrilateral with vertices d(0,0), i(5,5) n(8,4) g(7,1) is a KITE, as shown in figure a.

From the figure a, it is clear that the quadrilateral has

Two pairs of sides

Each pair having two equal-length sides which are adjacent

The angles being equal where the two pairs meet

Diagonals as shown in dashed lines cross at right angles,  and one of the diagonals does bisect the other - cuts equally in half

Please check the attached figure a.

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$1082

Step-by-step explanation:

10% of $984

10/100 ($984)= $98.4

Earnings = ($98.4+$984)

Earnings = $1082.4

Earnings = $1082 (to the nearest cent)

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 Well to be exact the answer is x=3 y=1
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What is the effect in the time required to solve a prob- lem when you double the size of the input from n to 2n, assuming that t
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Answer:

f(2n)-f(n)=log2

b.lg(lg2+lgn)-lglgn

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g. f(2n)/f(n)=2

Step-by-step explanation:

What is the effect in the time required to solve a prob- lem when you double the size of the input from n to 2n, assuming that the number of milliseconds the algorithm uses to solve the problem with input size n is each of these function? [Express your answer in the simplest form pos- sible, either as a ratio or a difference. Your answer may be a function of n or a constant.]

from a

f(n)=logn

f(2n)=lg(2n)

f(2n)-f(n)=log2n-logn

lo(2*n)=lg2+lgn-lgn

f(2n)-f(n)=lg2+lgn-lgn

f(2n)-f(n)=log2

2.f(n)=lglgn

F(2n)=lglg2n

f(2n)-f(n)=lglg2n-lglgn

lg2n=lg2+lgn

lg(lg2+lgn)-lglgn

3.f(n)=100n

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f(2n)/f(n)=200n/100n

f(2n)/f(n)=2

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4.f(n)=nlgn

f(2n)=2nlg2n

f(2n)-f(n)=2nlg2n-nlgn

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2nLg2+2nlgn-nlgn

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5.we shall look for the ratio

f(n)=n^2

f(2n)=2n^2

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the time will be times 4 the initial tiote tat ratio are used because it will be easier to calculate and compare

6.n^3

f(n)=n^3

f(2n)=(2n)^3

f(2n)/f(n)=(2n)^3/n^3

f(2n)/f(n)=8

the ratio will be times 8 the initial

7.2n

f(n)=2n

f(2n)=2(2n)

f(2n)/f(n)=2(2n)/2n

f(2n)/f(n)=2

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