Answer:
D, 344
Step-by-step explanation:
5x6 = 30x2 = 60
6x10 = 60
5x10 = 50x4 = 200
4x6=24 (dont need to divide by two since theres two triangles)
24+60+60+200= 344
since it has a diameter of 28, then its radius must be half that or 14.
![\textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=14 \end{cases}\implies A=\pi (14)^2\implies A=196\pi ~\hfill \stackrel{\stackrel{semi-circle}{half~that}}{98\pi }](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20circle%7D%5C%5C%5C%5C%20A%3D%5Cpi%20r%5E2~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D14%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Cpi%20%2814%29%5E2%5Cimplies%20A%3D196%5Cpi%20~%5Chfill%20%5Cstackrel%7B%5Cstackrel%7Bsemi-circle%7D%7Bhalf~that%7D%7D%7B98%5Cpi%20%7D)
We need to find the difference first. 65 - 60 = 5. Now we must find what percent 5 is of 65. It is 7,7%. The number decreased, and so it is a 7,7% decrease.
Answer:
S.I= 640
Step-by-step explanation:
I=prt
where p= $8,000
and r= 4%
and t= 2 years
$8,000×4%×2
8,000×4/100×2
80×4×2
=640
Therefore The S.I = 640.
<span>The arcs must intersect because the point at which the arcs intersect forms the halfway point of the angle; if they don’t intersect, the angle will not be bisected. </span>
