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CaHeK987 [17]
3 years ago
12

Evaluate D57C-76CA in base 16​

Mathematics
1 answer:
Nonamiya [84]3 years ago
8 0

c₁₆ - a₁₆ = 12 - 10 = 2₁₆

7 < c = 12 in base 16, so borrow 1 from the next place value:

17₁₆ - c₁₆ = 23 - 12 = 11 = b₁₆

In the next place, we replace 5 with 4, but 4 < 6, so borrow 1 from the next place value again:

14₁₆ - 6₁₆ = 20 - 6 = 14 = e₁₆

Replace d with c, so that

c₁₆ - 7₁₆ = 12 - 7 = 5₁₆

and this gives

d57c₁₆ - 76ca₁₆ = 5eb2₁₆

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Answer:

a) p-hat (sampling distribution of sample proportions)

b) Symmetric

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Step-by-step explanation:

a) This distribution is called the <em>sampling distribution of sample proportions</em> <em>(p-hat)</em>.

b) The shape of this distribution is expected to somewhat normal, symmetrical and centered around 16%.

This happens because the expected sample proportion is 0.16. Some samples will have a proportion over 0.16 and others below, but the most of them will be around the population mean. In other words, the sample proportions is a non-biased estimator of the population proportion.

c) The variability of this distribution, represented by the standard error, is:

\sigma=\sqrt{p(1-p)/n}=\sqrt{0.16*0.84/40}=0.058

d) The formal name is Standard error.

e) If we divided the variability of the distribution with sample size n=90 to the variability of the distribution with sample size n=40, we have:

\frac{\sigma_{90}}{\sigma_{40}}=\frac{\sqrt{p(1-p)/n_{90}} }{\sqrt{p(1-p)/n_{40}}}}= \sqrt{\frac{1/n_{90}}{1/n_{40}}}=\sqrt{\frac{1/90}{1/40}}=\sqrt{0.444}= 0.667

If we increase the sample size from 40 to 90 students, the standard error becomes two thirds of the previous standard error (se=0.667).

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3 years ago
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Answer:

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