Relaxin
<span>Relaxin, secreted by the corpus luteum of the ovary as well as the placenta, is responsible for helping to inhibit uterine activity and to soften the cervix and the collagen in joints. Softening of the cervix allows for dilatation at birth; softening of collagen allows for laxness in the lower spine and so helps enlarge the birth canal. The effect of estrogen is to cause breast and uterine enlargement. Progesterone has a major role in maintaining the endometrium, inhibiting uterine contractility, and aiding in the development of the breasts for lactation. Human placental lactogen (hPL), also known as human chorionic somatomammotropin, serves as an antagonist to insulin, making insulin less effective, thereby allowing more glucose to become available for fetal growth.</span>
Answer:
The correct answer is ATP and NADPH
Explanation:
During the light reaction, the light energy is absorbed by the chlorophyll pigment present in the thylakoid membrane which moves through different electron acceptors and allows the formation of NADPH and ATP.
This ATP and NADPH get utilized into the Calvin cycle during carbon fixation, reduction and regeneration steps. This utilization converts ATP and NADPH into ADP and NADP+. The energy released by them is used to fix carbon to produce organic compounds. Therefore the correct answer is ATP and NADPH.
13-13= 0, 19-13= 6, so then 0-6= -6
Answer:
This question lacks options, the options are:
A) FF and ff
B) FF and Ff
C) Ff and Ff
D) Ff and ff
The answer is D (Ff and ff for parent 1 and 2 respectively)
Explanation:
This question depicts a single gene coding for fur colour in mice. The gene controls two traits, black fur and white fur, encoded by alleles F and f respectively.
According to the question, a pair of mice has been bred several times to generate the same data of 22 black fur and 23 white fur mice. Based on this data, it shows that the phenotypic ratio of black to white mice is 1:1.
To get a 1:1 phenotypic ratio of black fur offspring to white fur offspring, the parents mice must have genotypes Ff (heterozygous) and ff (same recessive alleles).
In a cross between parents Ff × ff (see punnet square), offsprings with the following genotypes will be produced: Ff, Ff, ff and ff. Ff is black furred while ff is white furred.
Ff (2) : ff (2) is equivalent to Ff (1) : ff (1).
Hence, a data of 22 black mice and 23 white mice which represents a 1:1 ratio will only be produced by parents mice with genotypes: Ff and ff.
