The area of the shaded part in figure A and B are 2m² and 49 m² respectively.
<h3>Area of the shaded part</h3>
To determine the area, we must know the shape of the shaded part.
After identifying the shape, we move further to know the formula for such shape
From the figures given in A, we can see that the shaded region is in form of a triangle
a. The area of a right angle is given as;
The base multiplied by the half the height and vice versa
It is written mathematically as;
Area = 1/ 2 × base × height
Where
base = 2m
height = 2m
Substitute into the formula
Area = 1/ 2 × 2 × 2
Area = 2m²
For figure B, the shaded part is a rectangle
The formula for area of a rectangle is given as;
the width multiplied by the length
Area = width × length
Where width = 7m
length = 7m
Area = 7 × 7
Area = 49m ²
Thus, the area of the shaded part in figure A and B are 2m² and 49 m² respectively.
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Answer:
2√6 ft
Step-by-step explanation:
Tan Ф = opposite/ adjacent
tan 60 = t / 2√2 ft
tan 60 = √3
t = (tan 60 )(2√2 ft)
t = (√3)(2√2 ft) = 2√6 ft
Basically you can graph a function, for example a parabola by following the step pattern 1,35...
If you take the "standard" parabola, y = x², which has it's vertex at the origin (0, 0), then:
<span>➊ one way you can use a "step pattern" is as follows: </span>
<span>Starting from the vertex as "the first point" ... </span>
<span>OVER 1 (right or left) from the vertex point, UP 1² = 1 from the vertex point </span>
<span>OVER 2 (right or left) from the vertex point, UP 2² = 4 from the vertex point </span>
<span>OVER 3 (right or left) from the vertex point, UP 3² = 9 from the vertex point </span>
<span>OVER 4 (right or left) from the vertex point, UP 4² = 16 from the vertex point </span>
<span>and so on ... </span>
<span>where the "UP" numbers are the sequence of "PERFECT SQUARE" numbers ... </span>
<span>but always counting from the VERTEX EACH time. </span>
<span>➋ another way you can use a "step pattern" is just as you were doing: </span>
<span>Starting with the vertex as "the first point" ... </span>
<span>over 1 (right or left) from the LAST point, up 1 from the LAST point </span>
<span>over 1 (right or left) from the LAST point, up 3 from the LAST point </span>
<span>over 1 (right or left) from the LAST point, up 5 from the LAST point </span>
<span>over 1 (right or left) from the LAST point, up 7 from the LAST point </span>
<span>and so on ... </span>
<span>where the "UP" numbers are the sequence of "ODD" numbers ... </span>
<span>but always counting from the LAST point EACH time. </span>
<span>The reason why both Step Patterns Systems work is that set of PERFECT SQUARE numbers has the feature that the difference between consecutive members is the set of ODD numbers. </span>
<span>For your set of points, the vertex (and all the others) are simply "down 3" from the "standard places": </span>
<span>Standard {..., (-3, 9), (-2, 4), (-1, 1), (0, 0), (1, 1), (2, 4), (3, 9), ...} </span>
<span>shift ↓ 3 : {..., (-3, 6), (-2, 1), (-1, -2), (0, -3), (1,-2), (2, 1), (3, 6), ...} </span>