The dimensions that would result to maximum area will be found as follows:
let the length be x, the width will be 32-x
thus the area will be given by:
P(x)=x(32-x)=32x-x²
At maximum area:
dP'(x)=0
from the expression:
P'(x)=32-2x=0
solving for x
32=2x
x=16 inches
thus the dimensions that will result in maximum are is length=16 inches and width=16 inches
You do length times width times you get your area. (I think)
They should still be 280 miles apart on the map i belive.
You can multiply opposite sides, like so:
y*7 = 8*3
7y = 24
y = 24/7
19 4-cent stamps and 3 28-cent stamps should be used.
Given that Greg needs at least $ 1.60 in stamps to mail a package, and he has 28cent stamps and 4cent stamps, and he can use no more than twenty 4cent stamps as he only has one book left, to determine how many stamps to use should be made the following calculation, through a linear function:
- (0.04 x 20) + 0.28X = 1.60
- 0.80 + 0.28X = 1.60
- 0.28X = 1.60 - 0.80
- 0.28X = 0.80
- X = 0.8 / 0.28
- X = 2.85
- (3 x 0.28) + 0.04X = 1.60
- 0.84 + 0.04X = 1.60
- 0.04X = 1.60 - 0.84
- 0.04X = 0.76
- X = 0.76 / 0.04
- X = 19
Therefore, 19 4-cent stamps and 3 28-cent stamps should be used.
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