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3 years ago

PLEASE PLEASE PLEASE HELP!

Mathematics

2 answers:

vazorg [7]3 years ago

8 0

Answer:

6 13/30 1 9/10 2 8/15 2 37/40 miles in 2 days 1/4<3/10 5/6>7/10 23/24

Step-by-step explanation:

Elodia [21]3 years ago

7 0

Answer: Give him brainliest now (sorry for stealing points)

Step-by-step explanation:

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A piece of wire 19 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral tria

mr Goodwill [35]

Answer: 8.26 m

Step-by-step explanation:

$Let s be the length of the wire used for the square. \\Let $t$ be the length of the wire used for the triangle. \\Let $A_{S}$ be the area of the square. \\Let ${A}_{T}}$ be the area of the triangle. \\One side of the square is $\frac{s}{4}$ \\Therefore,we know that,$$A_{S}=\left(\frac{s}{4}\right)^{2}=\frac{s^{2}}{16}$

$The formula for the area of an equilateral triangle is, $A=\frac{\sqrt{3}}{4} a^{2}$ where $a$ is the length of one side,And one side of our triangle is $\frac{t}{3}$So,We know that,$$A_{T}=\frac{\sqrt{3}}{4}\left(\frac{t}{3}\right)^{2}$$We have to find the value of "s" such that,$\mathrm{s}+\mathrm{t}=19$ hence, $\mathrm{t}=19-\mathrm{s}$And$$A_{S}+A_{T}=A_{S+T}$

$$$Therefore,$$\begin{aligned}&A_{T}=\frac{\sqrt{3}}{4}\left(\frac{(19-s)}{3}\right)^{2}=\frac{\sqrt{3}(19-s)^{2}}{36} \\&A_{T+S}=\frac{s^{2}}{16}+\frac{\sqrt{3}(19-s)^{2}}{36}\end{aligned}$

$Differentiating the above equation with respect to s we get,$$A^{\prime}{ }_{T+S}=\frac{s}{8}-\frac{\sqrt{3}(19-s)}{18}$$Now we solve $A_{S+T}^{\prime}=0$$$\begin{aligned}&\Rightarrow \frac{s}{8}-\frac{\sqrt{3}(19-s)}{18}=0 \\&\Rightarrow \frac{s}{8}=\frac{\sqrt{3}(19-s)}{18}\end{aligned}$$Cross multiply,$$\begin{aligned}&18 s=8 \sqrt{3}(19-s) \\&18 s=152 \sqrt{3}-8 \sqrt{3} s \\&(18+8 \sqrt{3}) s=152 \sqrt{3} \\&s=\frac{152 \sqrt{3}}{(18+8 \sqrt{3})} \approx 8.26\end{aligned}$

$The domain of $s$ is $[0,19]$.So the endpoints are 0 and 19$$\begin{aligned}&A_{T+S}(0)=\frac{0^{2}}{16}+\frac{\sqrt{3}(19-0)^{2}}{36} \approx 17.36 \\&A_{T+S}(8.26)=\frac{8.26^{2}}{16}+\frac{\sqrt{3}(19-8.26)^{2}}{36} \approx 9.81 \\&A_{T+S}(19)=\frac{19^{2}}{16}+\frac{\sqrt{3}(19-19)^{2}}{36}=22.56\end{aligned}$

$$$Therefore, for the minimum area, $8.26 \mathrm{~m}$ should be used for the square$

8 0

2 years ago

Mark put his dog on a diet. The dog's total weight change for the first two weeks was -3/4 pound. The dog lost the same amount o

saw5 [17]

The change in the first week is .375 pounds =. Divide 3/4 by 2

8 0

4 years ago

 They spent $18 on tickets to the carnival and $36 on food.  They spent the rest of the money on g They spent $18 on tickets

Reptile [31]

Answer:

93 = g + 36 + 18

Step-by-step explanation:

8 0

3 years ago

Cameron buys mobile games via an app store on his phone. the relationship between the number of games downloaded, x, and the tot

kumpel [21]

Answer:

(1, 0.5)

Step-by-step explanation:

From the graph attached,

x-values are representing the number of games downloaded,

y - values are representing the total cost.

Unit rate means rate of 1 game downloaded.

If we represent this in terms of coordinates,

x- value (game downloaded) = 1

y - value (price of one game download) = $0.5

Therefore, point (1, 0.5) will represent the unit rate.

Option (2) on the top row will be the answer.

4 0

3 years ago

A number to the 10th power divided by the same number to the 7th power equals 125. What is the number?

sergeinik [125]

Answer:

Step-by-step explanation:

7 times 7 is 24

4 0

3 years ago