Answer:
Explanation:
Compute:
35 ÷ 16 = 2.1875 = 2R3
2 ÷ 16 = 0.125 = 0R2
Jot down the remainders:
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Let's look at another example: ![\sf 325_{10} = [?]_{16}](https://tex.z-dn.net/?f=%5Csf%20325_%7B10%7D%20%3D%20%5B%3F%5D_%7B16%7D)
Compute:
325 ÷ 16 = 20.3125 = 20R5
20 ÷ 16 = 1.25 = 1R4
1 ÷ 16 = 0.0625 = 0R1
Jot down remainders:
=====
![\sf 325_{10} = [145]_{16}](https://tex.z-dn.net/?f=%5Csf%20325_%7B10%7D%20%3D%20%5B145%5D_%7B16%7D)
Another example: ![\sf 500_{10} = [?]_{15}](https://tex.z-dn.net/?f=%5Csf%20500_%7B10%7D%20%3D%20%5B%3F%5D_%7B15%7D)
Compute:
500 ÷ 15 = 33.33... = 33R5
33 ÷ 15 = 2.2 = 2R3
2 ÷ 15 = 0.13... = 0R2
Jot down remainders:
=====
![\sf 500_{10} = [235]_{15}](https://tex.z-dn.net/?f=%5Csf%20500_%7B10%7D%20%3D%20%5B235%5D_%7B15%7D)
380
Do 4(-5) = -20
Then 4(100) = 400
Add -20+400=380
(You have to subtract because of the negative number but the answer is positive because the bigger number in the equation is positive)
Answer:
a) 87.7
b) g(t) = f(t)/2.2
Step-by-step explanation:
The number of pounds is 2.2 times the number of kilograms, so we have ...
f(t) = 2.2·g(t)
a) On day 37, Chase's weight in kg is ...
f(37) = 2.2g(37)
193 = 2.2g(37)
g(37) = 193/2.2
g(37) ≈ 87.7
__
b) Rearranging the equation we started with, we have ...
g(t) = f(t)/2.2
Answer:
A
Step-by-step explanation:
The constant rate of change in this question simply means the slope
To get the slope, we simply get two points and apply the slope equation;
The points are;
(3,60) and (6,30)
The slope equation is;
m = (y2-y1)/(x2-x1) = (30-60)/(6-3) = -30/3 = -10 ft/s
So our answer is the first option as it represents a decent of -10 ft/s
Answer:
if both sides are 33 its 1089
Step-by-step explanation:
33x33= 1089
answer= 1089²
