Answer:
- <u>59.0891 g (rounded to 4 decimal places)</u>
Explanation:
<em>Half-life time</em> of a radioactive substance is the time for half of the substance to decay.
Thus, the amount of the radioactive substance that remains after a number n of half-lives is given by:
Where:
- A is the amount that remains of the substance after n half-lives have elapses, and
- A₀ is the starting amount of the substance.
In this problem, you have that the half-live for your sample (polonium-210) is 138 days and the number of days elapsed is 330 days. Thus, the number of half-lives elapsed is:
- 330 days / 138 days = 2.3913
Therefore, the amount of polonium-210 that will be left in 330 days is:
The estimate should be 6.92
Answer:
8/100 is equivalent to 0.08
Answer:2
Step-by-step explanation: 5 - 3 = 2
Answer:
15x^3y+6x^2y^2+9xy^3
Step-by-step explanation:
3xy ( 5x^2 +2xy +3y^2)
Distribute the 3xy to all terms in the parentheses
3xy*5x^2+3xy*2xy+3xy*3y^2
15x^3y+6x^2y^2+9xy^3