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Lorico [155]
2 years ago
15

una camisa me costo $10.500, con lo que gaste el 25% de mi dinero ¿cuanto dinero tenia? debe ir desarrollo

Mathematics
1 answer:
evablogger [386]2 years ago
8 0

Answer:

25%------10500

100%------x = 100 * 10500 /25 = 42000

Rta: Tenías 42000

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Which inequality does the graph represent (pls I’m HORRIBLE at number lines so please answer both if possible, Ty)
notsponge [240]

Answer:

For #11 it is X≥-2.  For #12 it is X<-1 I think

Step-by-step explanation:

I hope this helps you and please mark me as brainliest

3 0
2 years ago
Select the correct answer.
alexgriva [62]

Answer:

D. 157

Step-by-step explanation:

4(x^2+3)-2y

4(6^2+3)-2(-1/2) add in given values

4(39)+1.     start with parentheses

156+1.        combine like terms

157.            answer

3 0
2 years ago
Read 2 more answers
Circle O has a circumference of approximately 44 in. What is the approximate length of the diameter, d? inches
LenKa [72]
The distance around a rectangle or a square is as you might remember called the perimeter. The distance around a circle on the other hand is called the circumference. It is calculated as follows:

C = 2pi(r)

From this, we can solve for r and evetually solve for the diameter.

44 = 2pi(r)
r = 7.00
d = 2r
d = 14

Read more on Brainly - brainly.com/sf/question/2502148
3 0
3 years ago
Read 2 more answers
If p=2—a then prove that a³+6ap+p³—8=0
GalinKa [24]
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5 0
3 years ago
If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar
erma4kov [3.2K]

Answer:

\frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}

Step-by-step explanation:

Given

5 tuples implies that:

n = 5

(h,i,j,k,m) implies that:

r = 5

Required

How many 5-tuples of integers (h, i, j, k,m) are there such thatn\ge h\ge i\ge j\ge k\ge m\ge 1

From the question, the order of the integers h, i, j, k and m does not matter. This implies that, we make use of combination to solve this problem.

Also considering that repetition is allowed:  This implies that, a number can be repeated in more than 1 location

So, there are n + 4 items to make selection from

The selection becomes:

^{n}C_r => ^{n + 4}C_5

^{n + 4}C_5 = \frac{(n+4)!}{(n+4-5)!5!}

^{n + 4}C_5 = \frac{(n+4)!}{(n-1)!5!}

Expand the numerator

^{n + 4}C_5 = \frac{(n+4)!(n+3)*(n+2)*(n+1)*n*(n-1)!}{(n-1)!5!}

^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5!}

^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5*4*3*2*1}

^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}

<u><em>Solved</em></u>

6 0
3 years ago
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