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Alenkinab [10]
3 years ago
11

Ginger's cat gave birth to a kitten that weighed 3 3/8 ounces when it was born. On the day Ginger sold the kitten to its new own

er, it weighed 5 1/2 ounces. How many ounces did the kitten gain before it went home with its new owner?
Mathematics
2 answers:
KiRa [710]3 years ago
8 0
The kitten grew 2.12 lbs
Oksanka [162]3 years ago
6 0

Answer:

i think it is c) 2 1/8

Step-by-step explanation:

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Please help
pychu [463]

Answer:

<h2>        y = x² - 1</h2>

Step-by-step explanation:

y = -1 for x = 0 {point(0, -1)} means -1 at the end of formula

If we add 1 to y-coordinate of  every given point we get the squares of x-coordinate:

(1, 0):   1² - 1 = 0

(2, 3):   2² - 1 = 4 - 1 = 3

(3, 8):   3² - 1 = 9 - 1 = 8

(4, 15):   4² - 1 = 16 - 1 = 15

So for any x:

(x, y)   y = x² - 1

6 0
3 years ago
Which of the following is true about a parallelogram? A. Opposite angles of a parallelogram are not congruent. B. Parallelograms
mafiozo [28]

Answer: The option is D.

Step-by-step explanation:

A line that intersects another line segment and separates it into two equal parts is called a bisector.

In a quadrangle, the line connecting two opposite corners is called a diagonal. We will show that in a parallelogram, each diagonal bisects the other diagonal.

Problem

ABCD is a parallelogram, and AC and BD are its two diagonals.  Show that AO = OC and that BO = OD

Strategy

Once again, since we are trying to show line segments are equal, we will use congruent triangles. And here, the triangles practically present themselves. Let’s start with showing that AO is equal in length to OC, by using the two triangles in which AO and OC are sides: ΔAOD and  ΔCOB.

There are all sorts of equal angles here that we can use. Several pairs of (equal) vertical angles, and several pairs of alternating angles created by a transversal line intersecting two parallel lines. So finding equal angles is not a problem. But we need at least one side, in addition to the angles, to show congruency.

As we have already proven, the opposite sides of a parallelogram are equal in size, giving us our needed side.

Once we show that ΔAOD and  ΔCOB are congruent, we will have the proof needed, not just for AO=OC, but for both diagonals, since BO and OD are alsocorresponding sides of these same congruent triangles.

ABCD is a parallelogram    

Given

AD || BC                                

From the definition of a parallelogram

AD = BC                                 Opposite sides of a parallelogram are equal in size

∠OBC ≅ ∠ODA                      Alternate Interior Angles Theorem, ∠OCB ≅ ∠OAD                      Alternate Interior Angles Theorem,

ΔOBC ≅ ΔODA                     

Angle-Side-Angle

BO=OD                                Corresponding sides in congruent triangles AO=OC                             Corresponding sides in congruent triangles.

5 0
3 years ago
Darius takes his family on an afternoon boat ride.
adelina 88 [10]
The statement that is true would be later on as he crosses Stover Lake, he drives 30 minutes at the same average speed. Hope this helps
6 0
3 years ago
In the past you paid $800
soldier1979 [14.2K]
Hello! $800 was the past amount for rent and now it's $900. 900 - 800 is 100. that's a $100 difference. In order to find the percent increase in the rent, we can write and sovle a proportion. It would be set up as change/original = x/100, where change is difference between two numbers and original is the previous price. It would be set up like this:

100/800 = x/100

Let's crossmultiply the values. 100 * 100 is 10,000. 800 * x is 800x. That makes 10,000 = 800x. Now, divide each side by 800 to isolate the x. 800x/800 cancels out. 10,000/800 is 12.5 or 12.5%. Let's check this by multiplying by 112.5%. 800 * 112.5% (1.125) is 900. That's what we're looking for! There. x = 12.5%. The percent increase is 12.5%.


5 0
3 years ago
Read 2 more answers
Write an appropriate direct variation equation if y = 8 when x = 4.
Snowcat [4.5K]

\bf \qquad \qquad \textit{direct proportional variation} \\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby \begin{array}{llll} k=constant\ of\\ \qquad variation \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \textit{we know that } \begin{cases} y=8\\ x=4 \end{cases}\implies 8=k4\implies \cfrac{8}{4}=k\implies 2=k \\\\[-0.35em] ~\dotfill\\\\ ~\hfill y=2x~\hfill

7 0
3 years ago
Read 2 more answers
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