Answer:
12 mph
Step-by-step explanation:
The relationship between jogging speed and walking speed means the time it takes to walk 4 miles is the same as the time it takes to jog 8 miles. Then the total travel time (0.75 h) is the time it would take to jog 1+8 = 9 miles. The jogging speed is ...
(9 mi)(.75 h) = 12 mi/h . . . average jogging speed
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<em>Check</em>
1 mile will take (1 mi)/(12 mi/h) = 1/12 h to jog.
4 miles will take (4 mi)/(6 mi/h) = 4/6 = 8/12 h to walk.
The total travel time is (1/12 +8/12) h = 9/12 h = 3/4 h. (answer checks OK)
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<em>Comment on the problem</em>
Olympic race-walking speed is on the order of 7.7 mi/h, so John's walking speed of 6 mi/h should be considered quite a bit faster than normal. The fastest marathon ever run is on the order of a bit more than 12 mi/h, so John's jogging speed is also quite a bit faster than normal. No wonder he got tired.
The answer should be 26 hours
105.0, 105%.
If one question is bonus, there are technically 20 questions on the test; 100/20 is 5, so each question is worth 5 points. 105 is 105% of 100.
Answer:
36
Step-by-step explanation:
6(2b - 4)
~Substitute
6(2(5) - 4)
~Simplify
6(10 - 4)
~Subtract in parenthesis
6(6)
~Multiply
36
Best of Luck!
<span>x in (-oo:+oo)
(x+20)/2 = 3*x // - 3*x
(x+20)/2-(3*x) = 0
(x+20)/2-3*x = 0
(x+20)/2+(-3*2*x)/2 = 0
x-3*2*x+20 = 0
20-5*x = 0
(20-5*x)/2 = 0
(20-5*x)/2 = 0 // * 2
20-5*x = 0
20-5*x = 0 // - 20
-5*x = -20 // : -5
x = -20/(-5)
x = 4 so x= 4</span>
