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2 years ago

Where is the point 7-10 located in the coordinate plane ?

Mathematics

1 answer:

Gemiola [76]2 years ago

5 0

Answer:

B) In Quadrant IV

Step-by-step explanation:

You move 7 units to the right on the x-axis. Then you move 10 units down the y-axis. The point will then land on quadrant IV.

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larisa [96]

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3 years ago

Identify the range of the following data set. 20, 22, 58, 48, 32, 20, 23

andrew-mc [135]

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2 years ago

Read 2 more answers

Hellp me solve this thanks

stellarik [79]

Answer:

c. 10 cm

Step-by-step explanation:

The parallel sides of trapizium are the bases so

base 1(B1) =9cm , base(B2)= 12cm

$area(a) = 105 {cm}^{2}$

the perpendicular distance means the height so lets find the height

area of trapizium= B1 + B2 × h

2

${105cm}^{2}(the \: given \: area) = \frac{9cm(the \: given \: base) + 12cm(the \: given \: base)}{2} \times h$

${105cm}^{2} = \frac{21cm}{2} \times h$

now we crisscross

${105cm}^{2} \times 2 = 21cm \times h$

${210cm}^{2} = 21cm \times h$

$\frac{ {210cm}^{2} }{21cm} = \frac{21cm \: }{21cm} \times h$

h = 10 cm

hope u like it ‍❤️‍‍❤️‍‍❤️‍

For any question comment me

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2 years ago

I NEED HELP!!!!!!!!!!!!!!!!!!

ratelena [41]

Answer:

thats easy

Step-by-step explanation:

but thanks 4 the points

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2 years ago

The picture is provided at the top.

Usimov [2.4K]

The answer for this problem is 4

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3 years ago