On the left side, we can collapse some terms:
Recall the double angle identity for cosine:
So we have
With the same reasoning, we can collapse that side further:
Answer: 0.07 (choice B)
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Explanation:
Let's define two events: B = hitting bullseye, and, T = hitting the third (outermost) ring
To figure out the probabilities of each event happening, we need to find the areas of each region. The bullseye is a circle with radius 6 inches (half of diameter 12), so the area is roughly...
A = pi*r^2 = pi*6^2 = 36pi
The radius of the outermost circle is 6+5+5 = 16 inches, leading to an area of
A = pi*r^2 = pi*16^2 = 256pi
So P(B) = (36pi)/(256pi) = 9/64 is the probability of hitting bullseye
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The area of the third ring is equal to the difference of the overall largest circle and the second largest circle.
The second largest circle has a radius of 6+5 = 11 inches with area pi*11^2 = 121pi square inches
So the third ring has an area of 256pi - 121pi = 135pi square inches
P(T) = probability of hitting the third ring
P(T) = (135pi)/(256pi)
P(T) = 135/256
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The last thing to do is to multiply the two probabilities P(B) and P(T). This works because the two events B and T are independent
P(B and T) = P(B)*P(T)
P(B and T) = (9/64)*(135/256)
P(B and T) = 0.07415771484376
P(B and T) = 0.07
I thinks it’s c but cover your name so people don’t see it
Answer: An easy way to determine whether a function is a one-to-one function is to use the horizontal line test on the graph of the function. To do this, draw horizontal lines through the graph. If any horizontal line intersects the graph more than once, then the graph does not represent a one-to-one function.
i dont know the exact answer but its a lil sum
Step-by-step explanation:
We know that for any two inverses f(x) = g(y), meaning that if we take f(x) for any x in the domain of f(x), then g(y), where y is the outcome of f(x), should output x. So that is a simple test to see if two functions are inverses.
