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3 years ago

Can someone help and please make sure answer is right :)

Mathematics

2 answers:

lesya692 [45]3 years ago

5 0

yes you are right the answer is 8

tester [92]3 years ago

3 0

Answer:

x=8

Step-by-step explanation:

The marked angles are corresponding angles, and are therefore equal:

7x-1=5x+15

2x=16

x=8

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For the inequality below, write the set of numbers in interval notation.

snow_tiger [21]

The answer would be [4, infinity)

4 0

3 years ago

If sin theta= 2/3 and tan theta<0, what is the value of cos theta

Sergeeva-Olga [200]

Cos
θ
=
√
5
3

or it could be cos
θ
=
√
5
−
3

Explanation:
Since sin
θ
is negative, it can be in the third or fourth quadrant
Drawing your right-angled triangle, place your
θ
in one of three corners. Your longest side will be 3 and the side opposite the
θ
will be -2. Finally, using Pythagoras theorem, your last side should be
√
5

Now, if your triangle was in the third quadrant, you would have
cos
θ
=
√
5
−
3
since cosine is negative in the third quadrant
But if your triangle was in the fourth quadrant, you would have
cos
θ
=
√
5
3
since cosine is positive in the fourth quadrant

8 0

3 years ago

Read 2 more answers

Can someone help me with factoring? 4x^3 + 43x^2 + 30x

Sergio039 [100]

$4x^{3}+43x^2+30x$
First in factoring, you must find out what is common in the whole equation
$x(4x^2+43x+30)$
Now, make 2 sets of parentheses and "split up" the rest of the equation
Try to experiment which numbers work out
We are not subtracting anything so both parentheses are positive
$x(4x+3)(x+10)$
Therefore, the factored version of $4x^3+43^2+30x$ is
$x(4x+3)(x+10)$

5 0

3 years ago

Part F What is the mean absolute deviation for Doctor A’s data set on glasses? What is the mean absolute deviation for Doctor B’

frez [133]

There is more variability on glasses of doctor B's dataset than the glasses of doctor A's dataset

<h3>The doctors' mean absolute deviation on glasses</h3>

The dataset of doctor A is given as:

643 634 670 658 636 624 641 655 649 629

The dataset of doctor B is given as:

651 625 622 624 631 621 653 647 646 646

Using a statistical calculator, we have:

<u>Doctor A</u>

Doctor A: Mean Absolute Deviation (MAD) = 11.28
Doctor B: Mean Absolute Deviation (MAD) = 12

Hence, the mean absolute deviation is 11.28 for Doctor A’s and 12 for Doctor B’s data set on glasses

<h3>The variation of the two data</h3>

In a dataset, the larger the mean absolute deviations value, the larger the variation.

By comparison, 12 is greater than 11.28

Hence, there is more variability on glasses of doctor B's dataset than the glasses of doctor A's dataset

Read more about mean absolute deviation at:

brainly.com/question/3250070

#SPJ1

7 0

2 years ago

Jim's soccer team is making fruit baskets for a fundraiser. They have 88 peaches, 60 bananas, and 54 kiwis to use. If each baske

cluponka [151]

The greatest number of fruit baskets they can make is 2 with each one having 44 peaches, 30 bananas and 27 kiwis

<h3><u>Solution:</u></h3>

Jim’s fruit basket has 88 peaches, 60 bananas and 54 Kiwis to use.

If each basket have same number of each type, we have to determine the greatest number of fruit baskets they can make

We need to find greatest common factor of 88, 60 and 54

When we find all the factors of two or more numbers, and some factors are the same ("common"), then the largest of those common factors is the Greatest Common Factor.

<em><u>Greatest common factor of 88, 60 and 54:</u></em>

The factors of 54 are: 1, 2, 3, 6, 9, 18, 27, 54

The factors of 60 are: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60

The factors of 88 are: 1, 2, 4, 8, 11, 22, 44, 88

Then the greatest common factor is 2

On dividing the number of fruits by 2 we get

$\begin{array}{l}{\text { Apples in each basket }=\frac{88}{2}=44} \\\\ {\text { Bananas in each basket }=\frac{60}{2}=30} \\\\ {\text { Kiwis in each basket }=\frac{54}{2}=27}\end{array}$

Hence, there can be 2 basket with each one having 44 peaches, 30 bananas and 27 kiwis

6 0

4 years ago