The probabability of winning on at least 1 bet is equal to 1 less the probaility of not winning on either of the 6 bets.
The probability of not wining on any bet is independent of winning or not winning on any of the bets, so the combined probability is calculated as the product of each individual probability.
Each indivitual probability of not winning the is:
(number of not winning outcomes) / (number of possible outcomes) = 37 / 38.
Then, the combined probability of not winning the six times is: (1/38)*(37/38)*(37/38)*(37/38)*(37/38)*(37/38) =(37/38)^6
Therefore, the probability of winning at least one bet is:
= 1 - (37/38)^6 ≈ 1 - 0.973684 ≈ 0.03.
Answer: 0.03.
do 154 / 2 and then add 35 and that is how much they won. do 154 / 2 and then subtract 35 and that is how much they loss
70-35 I believe that’s write
Answer:
Step-by-step explanation:
We start off with 3.2n + 13.3 = 26.1.
We need to get n by itself.
Subtract 13.3 from both sides.
We end up with: 
Divide 3.2 on both sides to get n by itself.
Your final answer will be 2 157/500 for the decimal 2.314
