Ok so 2(4q+3)=4q-14
2.4q=8q
2.3=6
8q+6=4q-14
8q-4q=-14-6
4q=-20
q=-20/4
q=-5
Answer:
The Area of a Segment is the area of a sector minus the triangular piece (shown in light blue here). There is a lengthy reason, but the result is a slight modification of the Sector formula: Area of Segment = θ − sin(θ) 2 × r2 (when θ is in radians) Area of Segment = ( θ × π 360 − sin(θ)2 ) × r2 (when θ is in degrees)
Step-by-step explanation:
Answer:
15
x
−
24
Step-by-step explanation:
Perimeter (P) = 2 · Length(L) + 2 · Width (W) → P = 2L + 2W
Solve for either L or W (I am solving for L).
200 - 2W = 2L
(200 - 2W)/2 = L
100 - W = L
Area (A) = Length (L) · Width (W)
= (100 - W) · W
= 100W - W²
Find the derivative, set it equal to 0, and solve:
dA/dW = 100 - 2W
0 = 100 - 2W
W = 50
refer to the equation above for L:
100 - W = L
100 - 50 = L
50 = L
Dimensions for the maximum Area are 50 ft x 50 ft
Answer:
in the form 81 and 324
Step-by-step explanation:
Divide 405 in the ratio 3: 12.
3x+12x=405
15x=405
x=405:15
x=27
=> 3*27 and 12*27
81 and 324
in the form 81 and 324
