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3 years ago

How do you solve this ?

Mathematics

2 answers:

Sedbober [7]3 years ago

7 0

"The equals sign with the squiggly line above it is the sign for congruence."

Therefore, GHIJ is congruent to PQRO.

H is then known as 99°;

J as 85°;

R as 123°;

P as 53°;

and all of the sides' km as listed.

If I'm understanding the question correctly, it is asking you for the appropriate degree of J, which we see as 85°.

Hope this helped!

Sav [38]3 years ago

4 0

Answer:

what the person above me said XD

Step-by-step explanation:

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Answer this question to cheek you knowledge

Anuta_ua [19.1K]

Step-by-step explanation:

hg=4

if correct then can we become friends

3 0

3 years ago

you are given an 8-gallon jug filled with water and also two empty jugs: one that holds 5 gallons and other that holds 3 gallons

Yanka [14]

Answer:

Step-by-step explanation:

We will use following steps to measure exactly 4 gallons of water with the help of 5 gallons and 3 gallons empty jugs.

1). Fill 3 gallons jug completely.

2). Pour this 3 gallons of water into 5 gallons jug. Now we have 3 gallons of water in 5 gallons jug and 3 gallons jug empty.

We can add 2 gallons of water in the empty space of 5 gallons jug more.

3). Fill the 3 gallons jug with the water again.

4). Pour this water into 5 gallons jug which can hold 2 gallons of water more.

Now we have 5 gallons of jug filled fully and 1 gallon water remaining in the 3 gallons jug.

5). Empty the 5 gallons jug completely.

6). Pour the remaining 1 gallon of remaining water in 3 gallons jug into 5 gallons jug.

7). Fill the 3 gallons jug completely and pour it into 5 gallon jug.

8). Finally we have 4 gallons of water in the 5 gallons jug.

8 0

3 years ago

Need to write steps and solve thanks

nalin [4]

Answer:

The coordinates of endpoint V is (7,-27)

Solution:

Given that the midpoint of line segment UV is (5,-11) And U is (3,5).

To find the coordinates of V.

The formula for mid-point of a line segment is as follows,

Midpoint of UV is $\frac{x_{1}+x_{2}}{2}$ , $\frac{y_{1}+y_{2}}{2}$

As per the formula, $\frac{x_{1}+x_{2}}{2}$ =5, $\frac{y_{1}+y_{2}}{2}$ =-11

Here $x_{1}=3; y_{1}=5$

Substituting the value of $x_{1}$ we get,

$\frac{3+x_{2}}{2}$ =5

$3+x_{2}=5\times2$

$x_{2}=10-3$

$x_{2}=7$

Substituting the value of $x_{2}$ we get,

$\frac{5+y_{2}}{2}$ =-11

$5+y_{2}=-11\times2$

$y_{2}=-22-5$

$y_{2}=-27$

So, the coordinates of V is (7,-27)

7 0

3 years ago

A rectangular box is to have a square base and a volume of 12 ft3. If the material for the base costs $0.17/ft2, the material fo

katen-ka-za [31]

Answer:

(a)Length =2 feet

(b)Width =2 feet

(c)Height=3 feet

Step-by-step explanation:

Let the dimensions of the box be x, y and z

The rectangular box has a square base.

Therefore, Volume of the box $V=x^2z$

Volume of the box $=12 ft^3\\$

$Therefore, x^2z=12\\z=\frac{12}{x^2}$

The material for the base costs $\$0.17/ft^2$ , the material for the sides costs $\$0.10/ft^2$ , and the material for the top costs $\$0.13/ft^2$ .

Area of the base $=x^2$

Cost of the Base $=\$0.17x^2$

Area of the sides $=4xz$

Cost of the sides= $=\$0.10(4xz)$

Area of the Top $=x^2$

Cost of the Base $=\$0.13x^2$

Total Cost, $C(x,z) =0.17x^2+0.13x^2+0.10(4xz)$

Substituting $z=\frac{12}{x^2}$

$C(x) =0.17x^2+0.13x^2+0.10(4x)(\frac{12}{x^2})\\C(x)=0.3x^2+\frac{4.8}{x} \\C(x)=\dfrac{0.3x^3+4.8}{x}$

To minimize C(x), we solve for the derivative and obtain its critical point

$C'(x)=\dfrac{0.6x^3-4.8}{x^2}\\Setting \:C'(x)=0\\0.6x^3-4.8=0\\0.6x^3=4.8\\x^3=4.8\div 0.6\\x^3=8\\x=\sqrt[3]{8}=2$

Recall: $z=\frac{12}{x^2}=\frac{12}{2^2}=3\\$

Therefore, the dimensions that minimizes the cost of the box are:

(a)Length =2 feet

(b)Width =2 feet

(c)Height=3 feet

7 0

3 years ago

Probably of Carl solving the 10 problems if there's 20 to study and he knows 15 and ten of the 20 are on the test.

Vladimir79 [104]

Answer:

1/3

Step-by-step explanation:

Probability of solving ten problems by Carl

Given

Total number of problems = 20

Number of problems studied by Carl = 15

Number of problems out of the 20 set of problem coming in test is 10

Case I - All ten problems come from the set of known 15 question

10/15 * 10/20 = 1/3

8 0

2 years ago

How do you solve this ?​

How do you solve this ?