Given:
Vertex ===> (h, k) (2, 4)
The parabola passes through the point: (x, y) ==> (3, 6)
Let's find the equation of a parabola.
To find the equation, use the general equation of a parabola with vertex (h, k):

Where:
(h, k) ==> (2, 4)
(x, y) ==> (3, 6)
Substitute values into the general equation:

Subtract 4 from both sides:

Substitute 2 for a, and input the values of the vertex (h, k) in the general vertex equation:

Therefore, the equation of the parabola is:

ANSWER:
Answer:
y= -1x+7
Step-by-step explanation:
I believe this is the correct answer. The graph starts at 7 which is the y-intercept. And starts declining my -1
(12x^3-4x^2+8x)/(-2x) The greatest common factor of the numerator and denominator is -2x so upon division by GCF of both numerator and denominator you have:
-6x^2+2x-4 and we can now also factor out -2
-2(3x^2-x+2)
Answer:
The box to the left will have the equation p(x) = 5x² and the box to the right will have the equation n(x) = 
Step-by-step explanation:
The coefficient of the x² decides how wide or narrow a quadratic graph is. If the coefficient is a fraction of 1, the smaller the fraction the wider the graph gets. If the coefficient is a number bigger than 1, the bigger the number, the narrower the graph gets.