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3 years ago

Are the expressions -0.5(3x + 5) and -1.5x + 2.5 equivalent? Explain why or why not.

Mathematics

2 answers:

ioda3 years ago

5 0

Sample Response:

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Using the distributive property to expand the first expression, you would get -1.5x - 2.5. Since the constant term does not have the same sign as the second expression, the two expressions are not equivalent. Also, if you substitute in a value for x and evaluate each expression, the values will not be equal.

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inysia [295]3 years ago

3 0

Answer:

Sample response: Using the distributive property to expand the first expression, you would get -1.5x - 2.5. Since the constant term does not have the same sign as the second expression, the two expressions are not equivalent. Also, if you substitute in a value for x and evaluate each expression, the values will not be equal.

Step-by-step explanation:

It's the simple response

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Sveta_85 [38]

Answer:

Step-by-step explanation:

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2 years ago

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slamgirl [31]

Answer: standard form is

Ax + Bx= C

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3x+8y=55

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Step-by-step explanation:

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2 years ago

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Allen's hummingbird (Selasphorus sasin) has been studied by zoologist Bill Alther.â Suppose a small group of 11 Allen's humming

alexira [117]

Answer:

$3.15-1.28\frac{0.38}{\sqrt{11}}=3.003$

$3.15+ 1.28\frac{0.38}{\sqrt{11}}=3.297$

So on this case the 80% confidence interval would be given by (3.003;3.297)

And the margin of error is given by:

$ME = 1.28\frac{0.38}{\sqrt{11}}= 0.147$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=3.15$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=0.38$ represent the population standard deviation

n=11 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.80 or 80%, the value of $\alpha=0.2$ and $\alpha/2 =0.1$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NOR.INV(0.1,0,1)".And we see that $z_{\alpha/2}=1.28$

Now we have everything in order to replace into formula (1):

$3.15-1.28\frac{0.38}{\sqrt{11}}=3.003$

$3.15+ 1.28\frac{0.38}{\sqrt{11}}=3.297$

So on this case the 80% confidence interval would be given by (3.003;3.297)

And the margin of error is given by:

$ME = 1.28\frac{0.38}{\sqrt{11}}= 0.147$

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3 years ago

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masya89 [10]

It was complicated but I did it

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3 years ago

What is the sum of 9c+(8+3c)?

mixas84 [53]

9c+(8+3c)
9c+8+3c (collect like terms)

9c+3c+8
12c+8

12c+8 is the answer.
im not sure if your teacher also wants the answer to be in simplest form so im going to do that below as well:

12c+8 (4*3=12 and 4*2=8. you can take out a 4 from those 2 numbers)

4(3c+2) (this is the simplest form of 9c+(8+3c))

6 0

2 years ago