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3 years ago

15

Pls help!! given: angles 1 and 2 are a linear pair prove that x=11

1 answer:

FinnZ [79.3K]3 years ago

6 0

Step-by-step explanation:

2. Given: Angles 1 and 2 are a linear pair. Prove that x = 11 ma m = 11x-6 m2 = 4x+21 Statements Reasons 1) Angles 1 and 2 are a linear pair. 1) Given 2) Angles 1 and 2 are 2) Linear Pair Postulate supplementary 3) mZ1 + m2 = 180° 3) 4) 11x - 6 + 4x + 21 = 180 4) 5) 15x + 15 = 180 5) 6) 15x = 165 6) 7) x = 11 7)

I am not sure about my answer i dont want u to get wrong this is all i know i hope it was helpful

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What is the perimeter of the trapezoid with vertices Q(8, 8), R(14, 16), S(20, 16), and T(22, 8)? Round to the nearest hundredth

uysha [10]

Answer:

The perimeter of the trapezoid is $38.25\ units$

Step-by-step explanation:

we know that

The perimeter of the trapezoid is the sum of its four side lengths

so

In this problem

$P=QR+RS+ST+QT$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

$Q(8, 8), R(14, 16), S(20, 16),T(22, 8)$

step 1

Find the distance QR

$Q(8, 8), R(14, 16)$

substitute the values in the formula

$d=\sqrt{(16-8)^{2}+(14-8)^{2}}$

$d=\sqrt{(8)^{2}+(6)^{2}}$

$d=\sqrt{100}$

$QR=10\ units$

step 2

Find the distance RS

$R(14, 16), S(20, 16)$

substitute the values in the formula

$d=\sqrt{(16-16)^{2}+(20-14)^{2}}$

$d=\sqrt{(0)^{2}+(6)^{2}}$

$d=\sqrt{36}$

$RS=6\ units$

step 3

Find the distance ST

$S(20, 16),T(22, 8)$

substitute the values in the formula

$d=\sqrt{(8-16)^{2}+(22-20)^{2}}$

$d=\sqrt{(-8)^{2}+(2)^{2}}$

$d=\sqrt{68}$

$ST=8.25\ units$

step 4

Find the distance QT

$Q(8, 8),T(22, 8)$

substitute the values in the formula

$d=\sqrt{(8-8)^{2}+(22-8)^{2}}$

$d=\sqrt{(0)^{2}+(14)^{2}}$

$d=\sqrt{196}$

$QT=14\ units$

step 5

Find the perimeter

$P=10+6+8.25+14=38.25\ units$

6 0

3 years ago

Read 2 more answers

alpha and beta are the zeros of the polynomial x^2 -(k +6)x +2(2k -1). Find the value of k if alpha + beta = 1/2 alpha beta(ITS

serious [3.7K]

Answer:

$k=\frac{-11}{2}$ .

Step-by-step explanation:

We are given $\alpha$ and $\beta$ are zeros of the polynomial $x^2-(k+6)x+2(2k-1)$ .

We want to find the value of $k$ if $\alpha+\beta=\frac{1}{2}$ .

Lets use veita's formula.

By that formula we have the following equations:

$\alpha+\beta=\frac{-(-(k+6))}{1}$ (-b/a where the quadratic is ax^2+bx+c)

$\alpha \cdot \beta=\frac{2(2k-1)}{1}$ (c/a)

Let's simplify those equations:

$\alpha+\beta=k+6$

$\alpha \cdot \beta=4k-2$

If $\alpha+\beta=k+6$ and $\alpha+\beta=\frac{1}{2}$ , then $k+6=\frac{1}{2}$ .

Let's solve this for k:

Subtract 6 on both sides:

$k=\frac{1}{2}-6$

Find a common denominator:

$k=\frac{1}{2}-\frac{12}{2}$

Simplify:

$k=\frac{-11}{2}$ .

7 0

3 years ago

John is gliding along on his scooter at a speed of 2.8 m/s when

user100 [1]

Answer:

18.67 m/s²

Step-by-step explanation:

a = ∆v/ t

a= v - u/t

a = 2.8 - 0 / 0.15

a = 2.8 / 0.15

a = 18.67 m/s²

3 0

3 years ago

What is the distance between the points?! round to the nearest tenth i need to show work

Contact [7]

Answer:

8.6

Step-by-step explanation:

To find the distance between two points we use the formula posted below

All we need to do is figure out what the points are on the graph and plug them into the formula... we end up with

the square root of (5-(-2)^2+(2-(-3)^2 and get the answer of 8.602325267

then we round to the nearest tenth and get 8.6

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3 years ago

Please help me with my homework.

Blababa [14]

Answer:

-3x + 6

Step-by-step explanation:

-3(x - 2) to find the equivalent of this expression, we need to multiply inside the parenthesis with -3 (with both x and -2)

-3(x - 2 = -3x + 6 (two negative expressions multiplied results in positive)

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3 years ago