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zysi [14]
3 years ago
9

Many adventures like to go rafting on the Colorado River through Grand Canyon National Park. There are many locations where the

river becomes more narrow, both the distance between the canyon walls as well as the depth changes due to debris like boulders on the bottom of the river; this leads to changes in the water speed. In the park, the Colorado River has an average width of 100m and an average depth of 8m, and an average speed of 3 m/s. At the Lava Falls Rapids, the river has an average width of about 25m and an average depth of about 15m. What is the approximate speed of the water in this location
Physics
1 answer:
GalinKa [24]3 years ago
6 0

Answer:

6.4 m/s

Explanation:

Given that :

The average width of the Colorado river = 100 m

Average depth of the river is = 8 m

Therefore, area = $A_1= 100 \ m \times 8 \ m$

Speed of the river, $v_1 = 3 \ m/s$

After the lava falls on the river,

Width of the river becomes = 25 m

Depth of the river became = 15 m

Therefore, area = $A_2= 25 \ m \times 15 \ m$

Now, since the volume flow rate of the Colorado river is same, then from the Continuity equation,

$Q_1=Q_2$

$A_1v_1=A_2v_2$

∴ $100 \times 8 \times3 = 25 \times 15 \times v_2$

$v_2=\frac{100 \times 8 \times 3}{25 \times 15}$

    = 6.4 m/s

Therefore, the speed of the river in this location is 6.4 m/s

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620 J of heat is added to the cylinder of an engine, which causes the gas inside to expand. As a result, the piston of the engin
Maru [420]

Answer:

<u>400</u> J work is done BY the engine.

The internal energy of the gas is <u>620</u> J

Explanation:

The given information are;

The heat added to the cylinder = 620 J

The force applied by the piston of the engine = 8.0 kN = 8,000 N

The distance over which the force moves (the piston) = 5.0 cm = 0.05 m

The work done (by the engine) = Force × Distance = 8,000 N × 0.05 m = 400 J

The internal energy is the sum of the kinetic and potential energy of the system

Therefore, given that the internal energy, U, is the sum total of the energy in the system

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<u>400</u> J work is done BY the engine.

The internal energy of the gas is <u>620</u> J.

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3 years ago
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yarga [219]
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How much power is generated if 375 J of work is done in 15 s?
erma4kov [3.2K]

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Question is down below
rosijanka [135]

The vertical components of velocity is 10.35 m/s and the horizontal component of velocity is 38.6 m/s

<h3>What are the components of velocity?</h3>

We know that velocity is a vector quantity, a vector often can be resolved into its components. The vertical components is V sinθ while the horizontal component is vcosθ.

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Vertical component = 40 m/s sin 15 degrees = 10.35 m/s

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