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zysi [14]
3 years ago
9

Many adventures like to go rafting on the Colorado River through Grand Canyon National Park. There are many locations where the

river becomes more narrow, both the distance between the canyon walls as well as the depth changes due to debris like boulders on the bottom of the river; this leads to changes in the water speed. In the park, the Colorado River has an average width of 100m and an average depth of 8m, and an average speed of 3 m/s. At the Lava Falls Rapids, the river has an average width of about 25m and an average depth of about 15m. What is the approximate speed of the water in this location
Physics
1 answer:
GalinKa [24]3 years ago
6 0

Answer:

6.4 m/s

Explanation:

Given that :

The average width of the Colorado river = 100 m

Average depth of the river is = 8 m

Therefore, area = $A_1= 100 \ m \times 8 \ m$

Speed of the river, $v_1 = 3 \ m/s$

After the lava falls on the river,

Width of the river becomes = 25 m

Depth of the river became = 15 m

Therefore, area = $A_2= 25 \ m \times 15 \ m$

Now, since the volume flow rate of the Colorado river is same, then from the Continuity equation,

$Q_1=Q_2$

$A_1v_1=A_2v_2$

∴ $100 \times 8 \times3 = 25 \times 15 \times v_2$

$v_2=\frac{100 \times 8 \times 3}{25 \times 15}$

    = 6.4 m/s

Therefore, the speed of the river in this location is 6.4 m/s

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A wall has a negative charge distribution producing a uniformhorizontal electric field. A small plastic ball of mass .01kg carry
Sauron [17]

Answer:

a)  E = -4 10² N / C , b) x = 0.093 m, c)     a = 10.31 m / s², θ=-71.9⁰

Explanation:

For that exercise we use Newton's second Law, in the attached we can see a free body diagram of the ball

X axis

             F_{e} - T_{x} = m a

Axis y

            T_{y} - W = 0

Initially the system is in equilibrium, so zero acceleration

            Fe = T_{x}  

            T_{y} = W

Let us search with trigonometry the components of the tendency

            cos θ = T_{y} / T

            sin θ = T_{x}  / T

           T_{y} = cos θ

           T_{x}  = T sin θ

We replace

            q E = T sin θ

            mg = T cosθ

             

a) the electric force is

                F_{e} = q E

                E = F_{e} / q

                E = -0.032 / 80 10⁻⁶

                E = -4 10² N / C

b) the distance to this point can be found by dividing the two equations

                q E / mg = tan θ

                θ = tan⁻¹ qE / mg

Let's calculate

              θ = tan⁻¹ (80 10⁻⁶ 4 10² / 0.01 9.8)

              θ = tan⁻¹ 0.3265

               θ = 18 ⁰

               sin 18 = x/0.30

               x =0.30 sin 18

               x = 0.093 m

c) The rope is cut, two forces remain acting on the ball, on the x-axis the electric force and on the axis and the force gravitations

X axis

           F_{e} = m aₓ

            aₓ = q E / m

           aₓ = 80 10⁻⁶ 4 10² / 0.01

           aₓ = 3.2 m / s²

Axis y

           W = m a_{y}

           a_{y} = g

           a_{y} = 9.8 m/s²

The total acceleration is can be found using Pythagoras' theorem

             a = √ aₓ² + a_{y}²

             a = √ 3.2² + 9.8²

             a = 10.31 m / s²

The Angle meet him with trigonometry

               tan θ = a_{y} / aₓ

               θ = tan⁻¹ a_{y} / aₓ

               θ = tan⁻¹ (-9.8) / 3.2

               θ = -71.9⁰

Movement is two-dimensional type with acceleration in both axes

8 0
3 years ago
Use this table of a school bus during morning pickups to answer the question.
AlexFokin [52]

Answer:

3.5

Explanation:

The answer should be 3.5

5 0
3 years ago
Read 2 more answers
Two balloons are charged with an identical quantity and type of charge: -6.25 x 10-6 C. They are held apart at a separation dist
steposvetlana [31]

Answer:

The electric force between them is 878.9 N

Explanation:

Given:

Identical charge q = -6.25 \times 10^{-6}C

Separation between two charges r = 0.02 m

For finding the electrical force,

According to the coulomb's law

   F = \frac{k q^{2} }{r^{2} }

Here, force between two balloons are repulsive because both charges are same.

Where k = 9 \times 10^{9}

   F = \frac{9 \times 10^{9} \times (-6.25 \times 10^{-6} )^{2}  }{4 \times 10^{-4} }

   F = 878.9 N

Therefore, the electric force between them is 878.9 N

8 0
3 years ago
Humans can hear the squeaks and clicks that bats emit while using echolocation to see their surroundings
MA_775_DIABLO [31]

Answer:

False?

Explanation:

Hope this helps you!

If this is wrong next time I will be better!

5 0
3 years ago
Read 2 more answers
An avant-garde composer wants to use the Doppler effect in his new opera. As the soprano sings, he wants a large bat to fly towa
Allisa [31]

Answer:

     v’= 9.74 m / s

Explanation:

The Doppler effect is due to the relative movement of the sound source and the receiver of the sound, in this case we must perform the exercise in two steps, the first to find the frequency that the bat hears and then the frequency that the audience hears that also It is sitting.

Frequency shift heard by the murciela, in case the source is still and the observer (bat) moves closer

        f₁ ’= f₀ (v + v₀)/v

         

Frequency shift emitted by the speaker in the bat, in this case the source is moving away from the observer (public sitting) that is at rest

         f₂’= f₁’ v/(v - vs)

           

Note that in this case the bat is observant in one case and emitter in the other, called its velocity v’

            v’= vo = vs

Let's replace

           f₂’= f₀   (v + v’)/v   v/(v -v ’)

           f₂’= f₀   (v + v’) / (v -v ’)

           (v –v’ ) f₂’ / f₀ = v + v ’

           v’ (1+ f₂’ /f₀) = v (f₂’/fo - 1)

           v’ (1 + 1.059) = 340 (1.059 - 1)

           v’= 20.06 / 2.059

           v’= 9.74 m / s

6 0
3 years ago
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