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ahrayia [7]
3 years ago
9

Difference between weightlessness in space and weightlessness in earth​

Physics
1 answer:
nadya68 [22]3 years ago
8 0
In space we feel weightlessness because the earths gravity has less effect on us.The Earths gravitational attraction at those altitudes is only about 11% less than it is at the Earths surface. If you had a ladder that could reach as high as the the shuttles orbit, your weight would be 11% less at the top.
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A lion has a mass of 45 kg. Answer the following questions about it, using correct units. a. The lion runs at a speed of 14.2 m/
Eva8 [605]
A) The kinetic energy of an object is given by:
K= \frac{1}{2}mv^2
where m is the mass of the object, and v its speed. For the lion in our problem, m=45 kg and v=14.2 m/s, so its kinetic energy is
K= \frac{1}{2}mv^2= \frac{1}{2}(45 kg)(14.2 m/s)^2=4537 J

b) the increase in gravitational potential energy of the lion is given by:
\Delta U = mg \Delta h
where g is the gravitational acceleration, and \Delta h is the increase in altitude of the lion. In this problem, \Delta h=28 m, so the increase in gravitational potential energy is
\Delta U=mg \Delta h=(45 kg)(9.81 m/s^2)(28 m)=12361 J

c) When the fox reaches the top of the tree, its gravitational potential energy is
U=mgh=(1.8 kg)(9.81 m/s^2)(3.8 m)=67 J
As it jumps, its kinetic energy is
K= \frac{1}{2}mv^2= \frac{1}{2}(1.8 kg)(8.1 m/s)^2=59 J
So the total mechanical energy of the fox as it jumps is
E=U+K=67 J + 59 J =126 J
6 0
3 years ago
Choose the word that best completes each sentence.
Igoryamba

Answer:

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4 0
3 years ago
Read 2 more answers
Problem: The frequency of an FM radio station is 89.3 MHz. Calculate its period. Part B: From the Library, select the general eq
vekshin1

Answer:

Time period, T=1.11\times 10^{-8}\ s

Explanation:

We have,

The frequency of an FM radio station is 89.3 MHz.

It is required to find the period of the wave.

The reciprocal of frequency is called time period of a wave. It can be given by :

T=\dfrac{1}{f}\\\\T=\dfrac{1}{89.3\times 10^{6}\ Hz}\\\\T=1.11\times 10^{-8}\ s

So, the period of the wave is 1.11\times 10^{-8}\ s.

5 0
2 years ago
Eukaryotic that can reproduce sexually contain two types of cells
Darina [25.2K]
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7 0
3 years ago
A 75-g bullet is fired from a rifle having a barrel 0.540 m long. choose the origin to be at the location where the bullet begin
lyudmila [28]
Part a) The work done by the gas on the bullet is the integral of the force in dx, where x is the distance covered by the bullet inside the barrel with respect to the origin:
W= \int\limits^{0.540m}_{0} {F} \, dx =  \int\limits^{0.540m}_{0} {(16000+10000x-26000x^2)} \, dx =
=16000x+10000  \frac{x^2}{2} - 26000  \frac{x^3}{3}
By substituting the length of the barrel, L=0.540 m, we find the total work done by the gas on the bullet:
W=16000(0.540m)+10000  \frac{(0.540m)^2}{2} - 26000  \frac{(0.540m)^3}{3}  =
=8733 J=8.73 kJ

part b) The resolution of the problem is the same, we just have to use the new length of the barrel (L=0.95 m) inside the final formula, and we find the new value of the work:
W=16000(0.95m)+10000  \frac{(0.95m)^2}{2} - 26000  \frac{(0.95m)^3}{3}  =
=12280 J=12.28 kJ
5 0
3 years ago
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