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Talja [164]
3 years ago
13

A car of mass 1270 kg makes a 15.0 m radius turn at 11.8 m/s on flat ground. How much centripetal force acts on it?

Physics
1 answer:
sergiy2304 [10]3 years ago
4 0

Answer:

11789 N

Explanation:

The following data were obtained from the question:

Mass (m) = 1270 kg

Radius (r) = 15 m

Velocity (v) = 11.8 m/s

Centripetal force (F) =?

The centripetal force that acted on the car can be obtained by using the following formula:

F = mv²/r

Where:

F is the centripetal force.

m is the mass.

v is the velocity.

r is the radius.

Thus, with the above formula, we can obtain the centripetal force as follow:

Mass (m) = 1270 kg

Radius (r) = 15 m

Velocity (v) = 11.8 m/s

Centripetal force (F) =?

F = mv²/r

F = 1270 × 11.8² / 15

F = 1270 × 139.24 / 15

F = 176834.8 / 15

F = 11789 N

Therefore, the centripetal force that acted on the car is 11789 N

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Explanation:

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let's use trigonometry to find the sinus

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  lam = 556,190 nmtea

we substitute

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we substitute in equation 1

         d y / L = m lam

         lam = dy / L m

let's reduce the magnitudes to the SI system

  d = 0.44 me = 0.44 10-3 m

  y = 5.5 mm = 5.5 10-3

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let's calculate

        lam = 0.44 10⁻³  5.5 10⁻³ / (4.2 1)

         

        lam = 5.76190 10⁻⁷ m

let's reduce to num

  lam = 5.56190 10⁻⁷ m (109 nm / 1m)

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