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2 years ago

A car of mass 1270 kg makes a 15.0 m radius turn at 11.8 m/s on flat ground. How much centripetal force acts on it?

Physics

1 answer:

sergiy2304 [10]2 years ago

4 0

Answer:

11789 N

Explanation:

The following data were obtained from the question:

Mass (m) = 1270 kg

Radius (r) = 15 m

Velocity (v) = 11.8 m/s

Centripetal force (F) =?

The centripetal force that acted on the car can be obtained by using the following formula:

F = mv²/r

Where:

F is the centripetal force.

m is the mass.

v is the velocity.

r is the radius.

Thus, with the above formula, we can obtain the centripetal force as follow:

Mass (m) = 1270 kg

Radius (r) = 15 m

Velocity (v) = 11.8 m/s

Centripetal force (F) =?

F = mv²/r

F = 1270 × 11.8² / 15

F = 1270 × 139.24 / 15

F = 176834.8 / 15

F = 11789 N

Therefore, the centripetal force that acted on the car is 11789 N

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The magnitude of the tension in the string marked A is 52.5N

Generally, the equation for is mathematically given as

Let's take θ be an angle at A

So, tanθ = 3/8

Let's take α be an angle at B (Below X)

tanα = 5/4

Let's take β be an angle at C (Below x)

tanβ = 1/6

First we take the Horizontal Components

74.9cos(9.46°) = Acos(20.6°) + Bcos(51.3°)

By solving the equation, we get

A = 78.9 - 0.668B … (1)

Now, we take the vertical components

74.9sin(9.46°) + Asin(20.6°) = Bsin(51.3°)

By solving the equation, we get

40.07 = 1.015B

B = 39.5N

By substituting the value of B in equation (1)

A = 78.9 - 0.6668× 39.5

A = 52.5N

Hence, the magnitude of the tension in the string marked A is 52.5N

Learn more about Tension here brainly.com/question/2287912

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2 years ago

Which statement correctly explains molecular motion in different states of matter using the kinetic theory?

Gelneren [198K]

the answer is the second one

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3 years ago

A bullet of mass 0.1 kg traveling horizontally at a speed of 100 m/s embeds itself in a block of mass 3 kg that is sitting at re

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Answer:

(a) the speed of the block after the bullet embeds itself in the block is 3.226 m/s

(b) the kinetic energy of the bullet plus the block before the collision is 500J

Explanation:

Given;

mass of bullet, m₁ = 0.1 kg

initial speed of bullet, u₁ = 100 m/s

mass of block, m₂ = 3 kg

initial speed of block, u₂ = 0

Part (A)

Applying the principle of conservation linear momentum, for inelastic collision;

m₁u₁ + m₂u₂ = v(m₁ + m₂)

where;

v is the speed of the block after the bullet embeds itself in the block

(0.1 x 100) + (3 x 0) = v (0.1 + 3)

10 = 3.1v

v = 10/3.1

v = 3.226 m/s

Part (B)

Initial Kinetic energy

Ki = ¹/₂m₁u₁² + ¹/₂m₂u₂²

Ki = ¹/₂(0.1 x 100²) + ¹/₂(3 x 0²)

Ki = 500 + 0

Ki = 500 J

Part (C)

Final kinetic energy

Kf = ¹/₂m₁v² + ¹/₂m₂v²

Kf = ¹/₂v²(m₁ + m₂)

Kf = ¹/₂ x 3.226²(0.1 + 3)

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3 years ago

A 42.2 kg sled is pulled forward

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net force = 143N - 111.36N

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2 years ago

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grigory [225]

Answer:

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As we know that

Intrinsic value or Price = Dividend ÷ (Cost of equity - growth rate)

where,

Cost of equity or ke is

= Risk free rate of return + beta × (Market rate of return - risk free rate of return)

= 6% + 0.75 × (14% - 6%)

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So the intrinsic value is

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3 years ago

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