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nekit [7.7K]
3 years ago
10

A pulley with a radius of 3.0 cm and a rotational inertia of 4.5 x 10^-3 kg∙m2 is suspended from the ceiling. A rope passes over

it with a 2.0-kg block attached to one end and a 4.0-kg block attached to the other. The rope does not slip on the pulley. At any instant after the blocks start moving the object with the greatest kinetic energy is:
Select one:

a. the heavier block

b. none (all three objects have the same kinetic energy)

c. none (all three objects have the same kinetic energy)

d. either block (the two blocks have the same kinetic energy)

e. the pulley
Physics
1 answer:
solmaris [256]3 years ago
3 0

Answer:

maximum kinetic energy is for Pulley

e) The pulley

Explanation:

Let 4 kg block is moving downwards with speed "v" so we can say that 2 kg block will move upwards with same speed "v"

Now we know that pulling is in pure rotational motion

so we will have

\omega = \frac{v}{R}

\omega = \frac{v}{0.03}

now kinetic energy of each is given as

For 4 kg block

K_1 = \frac{1}{2}(4)(v^2) = 2v^2

for 2 kg block

K_2 = \frac{1}{2}(2)(v^2) = v^2

For pulley

K_3 = \frac{1}{2}I\omega^2

K_3 = \frac{1}{2}(4.5\times 10^{-3})\frac{(v^2)}{0.03^2}

K_3 = 2.5 v^2

So maximum kinetic energy is for Pulley

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R= \frac{\rho L}{A}
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A is the cross-sectional area of the wire

The length of the wire is quadrupled, so if we call L the original length and L' the new length, we can write 
L'=4 L

Similarly, the radius of the wire is doubled (r'=2r), so the new area is
A'= \pi (r')^2 = \pi (2r)^2 = 4 \pi r^2 = 4A

And if we substitute into the equation, we find that the new resistance of the wire is
R'= \frac{\rho L'}{A'}= \frac{\rho (4L)}{4 A'}  =  \frac{\rho L}{A}=R
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Answer:

20 Hz

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Explanation:

A

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B

A 100-Hz sound must be 10^1.2 times or 15.8 times more intense compared to a 1000-Hz sound to be perceived as equal to 60 phons of loudness

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11. A vector M is 15.0 cm long and makes an angle of 20° CCW from x axis and another vector N is 8.0 cm long and makes an angle
Alja [10]

Answer:

The magnitude of the resultant vector is 22.66 cm and it has a direction of 29.33°

Explanation:

To find the resultant vector, you first calculate x and y components of the two vectors M and N. The components of the vectors are calculated by using cos and sin function.

For M vector you obtain:

M=M_x\hat{i}+M_y\hat{j}\\\\M=15.0cm\ cos(20\°)\hat{i}+15.0cm\ sin(20\°)\hat{j}\\\\M=14.09cm\ \hat{i}+5.13\ \hat{j}

For N vector:

N=N_x\hat{i}+N_y\hat{j}\\\\N=8.0cm\ cos(40\°)\hat{i}+8.0cm\ sin(40\°)\hat{j}\\\\N=6.12cm\ \hat{i}+5.142\ \hat{j}

The resultant vector is the sum of the components of M and N:

F=(M_x+N_x)\hat{i}+(M_y+N_y)\hat{j}\\\\F=(14.09+6.12)cm\ \hat{i}+(5.13+5.142)cm\ \hat{j}\\\\F=20.21cm\ \hat{i}+10.27cm\ \hat{j}

The magnitude of the resultant vector is:

|F|=\sqrt{(20.21)^2+(10.27)^2}cm=22.66cm

And the direction of the vector is:

\theta=tan^{-1}(\frac{10.27}{20.21})=29.93\°

hence, the magnitude of the resultant vector is 22.66 cm and it has a direction of 29.33°

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