The first thing we are going to do for this case is to model the igloo as a hemisphere.
The volume of the hemisphere is:
V = ((4/3) * (pi) * (r ^ 3)) / 2
Where,
r: sphere radio
We have then that the internal diameter is:
di = 12-1.5
di = 10.5 feet
So the radio is:
r = di / 2
r = 10.5 / 2
r = 5.25 feet
Substituting values:
V = ((4/3) * (pi) * ((5.25) ^ 3)) / 2
V = 303.1 feet ^ 3
Answer:
the amount of space of the living area inside the igloo is:
V = 303.1 feet ^ 3
<span><span>y = 2 + 2sec(2x)
The upper part of the range will be when the secant has the smallest
positive value up to infinity.
The smallest positive value of the secant is 1
So the minimum of the upper part of the range of
y = 2 + 2sec(2x) is 2 + 2(1) = 2 + 2 = 4
So the upper part of the range is [4, )
The lower part of the range will be from negative infinity
up to when the secant has the largest negative value.
The largest negative value of the secant is -1
So the maximum of the lower part of the range of
y = 2 + 2sec(2x) is 2 + 2(-1) = 2 - 2 = 0
So the lower part of the range is (, 0].
Therefore the range is (, 0] U [4, )
</span>
</span>
Answer:
w ≥ 6
Step-by-step explanation:
51 ≤ 15 +6w
51-15 ≤ 6w
36 ≤ 6w
6w ≥ 36
w ≥ 36/6
w ≥ 6
Answer:
Well the slope seems rather easy to calculate because you already typed it and it is 2.
First we must solve this equation:
b = y - m*x and we input values into the equation:
b = (3) - (2 * -1)
b = 5
Then, we enter the value of "b" and the slope into this equation:
y = mx +b
y = 2x + 5
Source: https://www.1728.org/distance.htm
(Scroll to the bottom of the page.)
Step-by-step explanation:
<span>f(x)=3x+8 and g(x)=6x+6
(f + g)(x) = f(x) + g(x)
= </span>3x+8 + (6x + 6) = 3x + 6x + 8 + 6 = 9x + 14<span>
</span>(f + g)(x) = <span> 9x + 14
</span>
(f + g)(-1) = <span> 9*-1 + 14 = -9 + 14 = 5
</span>
<span>(f + g)(-1) = 5</span>
