Let
x-------> the width of the rectangular area
y------> the length of the rectangular area
we know that
y=x+15------> equation 1
perimeter of a rectangle=2*[x+y]
2x+2y <= 150-------> equation 2
substitute 1 in 2
2x+2*[x+15] <=150--------> 2x+2x+30 <=150----> 4x <=150-30
4x <= 120---------> x <= 30
the width of the rectangular area is at most 30 ft
y=x+15
for x=30
y=30+15------> y=45
the length of the rectangular area is at most 45 ft
see the attached figure
the solution is<span> the shaded area</span>
Hope this helps
Given a term in a geometric sequence and the common ratio find the first five terms, the explicit formula, and the recursive formula. Given two terms in a geometric sequence find the 8th term and the recursive formula. Determine if the sequence is geometric. If it is, find the common ratio.
We can tell if this is a factor of the polynomial shown by using the remainder theorem.
First, we need to set x + 1 equal to 0.
x + 1 = 0
Now, we solve for x.
x = -1
Now, we can plug this value into the polynomial, and if the solution is 0, it means there is a remainder of 0, which means they divide perfectly.
(-1)^3 - 10(-1)^2 + 27(-1) - 12 = -50
x + 1 is not a factor of the provided polynomial.
Answer:
f(-2) = -5
f(0) = 5
f(1) = 10
Step-by-step explanation:
f(-2) = 5(-2) + 5 → -10 + 5 = -5
f(0) = 5(0) + 5 → 0 + 5 = 5
f(1) = 5(1) + 5 → 5 + 5 = 10