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Elodia [21]
3 years ago
6

Which table shows ordered pairs that satisfy function Y=x^2 + 1

Mathematics
1 answer:
DochEvi [55]3 years ago
7 0

Answer:

Plug in the x or y on the table and that should give you the x or y answer. Which ever one matches this is the correct answer.

Step-by-step explanation:

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Point V lies between points U and W on Line segment U W.
Nutka1998 [239]

Answer:

The correct answer is (d) 36 units.

Step-by-step explanation:

Just took the test on edge :)

5 0
3 years ago
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I'm stuck on this please help!!
kvv77 [185]
The answer is D
\frac{12 {x}^{6}  {y}^{ - 4} {z}^{2}  }{3 {x}^{2}  {y}^{ - 6}  {z}^{3} } \\  =  \frac{4 {x}^{4}  {y}^{2} }{z}
5 0
3 years ago
¿Cuál es el valor absoluto de 9?
Fantom [35]
Por lo que, el valor absoluto de -9 es 9. El valor absoluto de 9 es el número de unidades que está 9 del cero. Nueve está a nueve unidades de cero.
6 0
3 years ago
A rocket is launched straight up from the ground with an initial velocity of 192 feet per second. The equation for the height of
Ivenika [448]

The equation for the height of the rocket at time t given

h= -16t^2+192t

We have to find the time t, when the rocket reaches 560 feet.

That means we have to find t when h = 560 ft. we will place 560 in the place of h to find t now.

h= -16t^2+192t

560 = -16t^2+192t

In the right side, we can check -16 is the common factor. So we will take out -16 from the rigbht side.

560 = -16(t^2 - 12t)

To get rid of -16 from the right side and move it to left side, we will divide both sides by -16.

560/-16 = -16(t^2-12t)/-16

-35 = t^2 -12t

Now we will move -35 to the righ side by adding 35 to both sides.

-35+35 = t^2-12t+35

0 = t^2 -12t+35

t^2-12t+35 = 0

We will factorize thee left side to find the values of t now. We need to find a pair of factors of 35 that by adding them we will get -12.

The pair of factors of 35 are -5 and -7 and by adding -5-7 we will get -12.

t^2-12t+35 =0

(t-5)(t-7) =0

So by using zero product property we will get

t-5 =0

t-5+5 = 0+5

t=5

Also t-7 =0

t-7+7 = 0+7

t=7

So we have got the rocket reaches at 560ft when t = 5 seconds and also when t = 7 seconds.

Now part b.

When the rocket completes its trajectory and hits the ground then the height or h = 0. So we will place h = 0 there in the equation.

h= -16t^2+192t

0= -16t^2 + 192 t

0 = -16(t^2-12t)

-16(t^2-12t) = 0

We will move -16 to the other side by dividing it to both sides.

-16(t^2-12t)/-16 = 0/-16

t^2-12t = 0

We will take out the common factor t from the left side. By taking out t we will get,

t(t-12) = 0

We will use zero product property now. By using that we will get,

t = 0

ans also t-12 = 0

t-12+12 = 0+12

t = 12

When the rocket completes its trajectory and hits the ground the time t can not be 0. When t =0, the rocket starts the trajectory.

So when the rocket completes its trajectory and hits the ground ,

then t = 12seconds.

So we have got the required answers.

6 0
3 years ago
Mrs. Stevens is delivering flowers to a local flower shop. She delivers the same number of flowers with each delivery. The flowe
Zigmanuir [339]
513 flowers because if you divided 2,050 by 4 you get 512.5, but if you round you get 513
7 0
3 years ago
Read 2 more answers
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