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Romashka-Z-Leto [24]
3 years ago
6

I need help mainly the anwsers​

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
3 0

Answer:

3(-2)+2= -4

3(3)+2= 11

3(-0.5)+2= .5

3(1 1/2)+2=6.5

Step-by-step explanation:

just plug them in as x and you get the answer

You might be interested in
The ratio of tagged fish to untagged fish was 2 to 9. Ninety fish were tagged. How many fish were untagged
Nimfa-mama [501]

Answer:

405

Step-by-step explanation:

Since

2 : 9 = 90 : X

Then we know

9/2 = X/90

Multiplying both sides by 90 cancels on the right

90 × (9/2) = (X/90) × 90

90 × (9/2) = X

Then solving for X

X = 90 × (9/2)

X = 405

Therefore

2 : 9 = 90 : 405

5 0
3 years ago
A store sells candy at $.50, $1, $1.50, $2, and $3 per kilogram. you can see that the unit price of candies that $3 buy very inv
olga nikolaevna [1]

Answer:

constant of variation = 3

Step-by-step explanation:

Given that a store is selling different candies costing  $.50, $1, $1.50, $2, and $3 per kilogram.

As given

Amount available to buy candies = $ 3

Suppose

Unit price of candies = x

Number of candies bough = y

Constant of variation = k

As we know the unit price of candies and number of candies bought vary inversely. As the unit price would increase the the number of candies bought in available amount ($3) would decrease.

So our formula to calculate formula for constant of variation would be as shown below:

k= xy →(1

Case 1

if we take unit price x to be $0.5, then we can buy 6 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (0.5)(6) = 3

Case 2

if we take unit price x to be $1, then we can buy 3 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (1)(3) = 3

Case 3

if we take unit price x to be $1.5, then we can buy 2 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (1.5)(2) = 3

Case 4

if we take unit price x to be $2, then we can buy 1.5 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (2)(1.5) = 3

Case 4

if we take unit price x to be $3, then we can buy 1 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (3)(1) = 3

So, our constant of variation is 3.

3 0
3 years ago
Randy said that the number 0.03 has a value 10 times greater than 0.003.Is he correct ?Explain your answer.
ziro4ka [17]
Yes. When you multiply a decimal number by 10, the decimal point moves one point to the right. Example:

0.05*10 = 0.5

This means that 0.003*10=0.03 since the decimal point moved one place to the right.
3 0
3 years ago
Read 2 more answers
A randomly generated list of integers from 0 to 4 is being used to simulate an event, with the numbers 1, 2, and 3 representing
Tresset [83]

Answer:

I think the anwser is

<h2>C.60 percent</h2>

hope it helped

6 0
3 years ago
3
muminat

Answer:

y = 3x + 3

Step-by-step explanation:

when you check, only that equation delivers the correct x and y pairs.

x = 0, => y = 3×0 + 3 = 3

x = 1, y = 3×1 + 3 = 3+3 = 6

x = 2, y = 3×2 + 3 = 6 + 3 = 9

x = 3, y = 3×3 + 3 = 9 + 3 = 12

it all fits.

6 0
3 years ago
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