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3 years ago

13

The value of Maggie's car decreased by 25% since last year, when she bought it. If the car is now worth $11,000.00, how much was

the car worth when she bought it?

2 answers:

fredd [130]3 years ago

8 0

Answer: Do 1.25(19,000.00) and you get 23,750

Step-by-step explanation:

balandron [24]3 years ago

3 0

Your answer is 23,750

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A real estate agent works on 7% commission. What is her commission on a house that she sold for $210,600?

loris [4]

To find how much the real estate agent made, we must multiply the two.
Note: It is crucial that you put 7% as a decimal.

$210600*0.07= 14742$

Therefore, the real estate agent made $14,742

Hope this helps!

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3 years ago

Which of the following values of x make the following functions equal? y = 2x + 6 and

Papessa [141]

Answer:

the answers Is c. x=4

Step-by-step explanation:

do substitution 2*4+6=14

and 6*4-10=14

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2 years ago

CAN SOMEONE HELP ME WITH THIS PLEASE AND THANK YOU

sammy [17]

For this do 5/8-1/2!! in order to do this, find the common denominator. this one is 16, so do: 10/16-8/16, and simplify!

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3 years ago

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732,178+167-542,137=

madreJ [45]

( 732,178 + 167 ) = 899,178
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3 0

3 years ago

Read 2 more answers

Find the general indefinite integral. (Use C for the constant of integration. Remember to use absolute values where appropriate.

Maru [420]

Answer:

$9\text{ln}|x|+2\sqrt{x}+x+C$

Step-by-step explanation:

We have been an integral $\int \frac{9+\sqrt{x}+x}{x}dx$ . We are asked to find the general solution for the given indefinite integral.

We can rewrite our given integral as:

$\int \frac{9}{x}+\frac{\sqrt{x}}{x}+\frac{x}{x}dx$

$\int \frac{9}{x}+\frac{1}{\sqrt{x}}+1dx$

Now, we will apply the sum rule of integrals as:

$\int \frac{9}{x}dx+\int \frac{1}{\sqrt{x}}dx+\int 1dx$

$9\int \frac{1}{x}dx+\int x^{-\frac{1}{2}}dx+\int 1dx$

Using common integral $\int \frac{1}{x}dx=\text{ln}|x|$ , we will get:

$9\text{ln}|x|+\int x^{-\frac{1}{2}}dx+\int 1dx$

Now, we will use power rule of integrals as:

$9\text{ln}|x|+\frac{x^{-\frac{1}{2}+1}}{-\frac{1}{2}+1}+\int 1dx$

$9\text{ln}|x|+\frac{x^{\frac{1}{2}}}{\frac{1}{2}}+\int 1dx$

$9\text{ln}|x|+2x^{\frac{1}{2}}+\int 1dx$

$9\text{ln}|x|+2\sqrt{x}+\int 1dx$

We know that integral of a constant is equal to constant times x, so integral of 1 would be x.

$9\text{ln}|x|+2\sqrt{x}+x+C$

Therefore, our required integral would be $9\text{ln}|x|+2\sqrt{x}+x+C$ .

4 0

2 years ago