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vampirchik [111]
3 years ago
11

18/80 in simplest from

Mathematics
1 answer:
Vaselesa [24]3 years ago
6 0

Answer:

answer: 9/40

Step-by-step explanation:

18 ÷ 2 = 9 and 80 ÷ 2 = 40 and you can't go any further so 9/40 is the answer.

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A farmer plants twice as many acres of wheat as corn on his land. If he plants no more than 36 acres, what is the greatest numbe
Leona [35]

Answer: 12 acres could be planted (at most)

Step-by-step explanation: Since there will be twice as many acres of wheat in  comparison to the corn, out of the total 36 acres at least 24 of those will need to be wheat. That leaves 12 acres left for the corn.

6 0
3 years ago
A slide has a diagonal of 10 feet and covers a distance of 8 feet across the ground. How many feet high is the slide at its high
Tasya [4]

So, this creates a triangle once again. If we imagine a slide, the slide itself would be the hypotenuse of the triangle, then if there's a ladder leading up to the slide, that would be the vertical length we're looking for. The feet across the ground would be the distance from the bottom of the slide to the bottom of the ladder.

We can use the Pythagorean theorem to find the missing side length, as this would create a right triangle. | 8^2 + b^2 = 10^2 | 64 + b^2 = 100 | b^2 = 36 | b = 6 feet | The slide is 6 feet high at its highest point.

4 0
3 years ago
Need help with #8 plssssssssssssss
Aleksandr-060686 [28]
I'm sorry, I don't see the question. Could you please retake the photo in better quality so I could answer it? Thanks!
3 0
3 years ago
Prove that the triangle EDF is isosceles. Give reasons for your answer.
Gekata [30.6K]

Answer:

\triangle EDF is isosceles.

Step-by-step explanation:

Please have a look at the attached figure.

We are <u>given</u> the following things:

\angle EDF = y

\text{External }\angle DFG = 90 +\dfrac{y}{2}

Let us try to find out \angle E and \angle DFE. After that we will compare them.

<u>Finding </u>\angle DFE<u>:</u>

Side EG is a straight line so \angle GFE = 180

\angle GFE is sum of internal \angle DFE and external \angle DFG

\angle GFE = 180 = \angle DFE  + \angle DFG\\\Rightarrow 180 = \angle DFE + (90+\dfrac{y}{2})\\\Rightarrow \angle DFE = 180 - 90 - \dfrac{y}{2}\\\Rightarrow \angle DFE = 90 - \dfrac{y}{2} ....... (1)

<u>Finding </u>\angle E<u>:</u>

<u>Property of external angle:</u> External angle in a triangle is equal to the sum of two opposite internal angles of a triangle.

i.e. external \angle DFG = \angle E + \angle EDF

\Rightarrow 90+\dfrac{y}{2} = \angle E + y\\\Rightarrow \angle E = 90+\dfrac{y}{2}  -y\\\Rightarrow \angle E = 90-\dfrac{y}{2} ....... (2)

Comparing equations (1) and (2):

It can be clearly seen that:

\angle DFE = \angle E =90-\dfrac{y}{2}

The two angles of \triangle EDF are equal hence \triangle EDF is isosceles.

8 0
3 years ago
Please needed as soon as possible thank you
stich3 [128]

Answer:

43. = \frac{.0045}{100}

44. 4\frac{9}{10}

45. 8

Step-by-step explanation:

43. 0.45% = .0045

      = \frac{.0045}{100}

44. \frac{1}{2} • 9\frac{4}{5}

    = 4\frac{9}{10}

45. VIII = 8

3 0
3 years ago
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