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Kamila [148]
3 years ago
11

Out of 30 students surveyed, 17 have a dog. Based on these results, predict how many of the 300 students in the school have a do

g.
Mathematics
2 answers:
saw5 [17]3 years ago
6 0
So 17 out of 30 or 17/30
so we want to find the equivilent of 17/30 with the bottom number 300 so

we know that 1/2=4/8 because 1/2 times 4/4 ( or 1) =4/8 soo

we notice that 300 is 10 times of 30 so

17/30 times 10/10=170/300 so

170 student have a dog
Morgarella [4.7K]3 years ago
4 0
We know that 30 students have 17 dogs. If we want to know how many dogs will have 10 times more students (300) we can miltiply 17 times 10 as well to get the answer.
17*10=170 - its predicted value
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A certain town never has two sunny days in a row. Each day is classified as being either sunny, cloudy (but dry), or rainy. If i
11111nata11111 [884]

Answer:

the proportion of days that are Sunny is 0.2

Step-by-step explanation:

Given the data in the question;

Using markov chain;

3 states; Sunny(1), Cloudy(2) and Rainy(3)

Now, based on given conditions, the transition matrix can be obtained in the following way;

\left[\begin{array}{ccc}0&0.5&0.5\\0.25&0.5&0.25\\0.25&0.25&0.5\end{array}\right]

so let the proportion of sunny, cloudy and rainy days be S, C and R respectively.

such that, from column 1

S = 0.25C + 0.25R   -------------let this be equation 1

from column 2

0.5C = 0.5S + 0.25R

divided through by 0.5

C = S + 0.5R ---------------------- let this be equation 2

now putting equation 2 into equation;

S = 0.25(S + 0.5R) + 0.25R

S = 0.25S + 0.125R + 0.25R

S - 0.25S = 0.375R

0.75S = 0.375R

S = 0.375R / 0.75

S = 0.5R

Therefore,

from equation 2; C = S + 0.5R

input S = 0.5R

C = 0.5R + 0.5R

C = R

Now, we know that, the sum of the three proportion should be equal to one;

so

S + C + R = 1

since C = R and S = 0.5R

we substitute

0.5R + R + R = 1

2.5R = 1

R = 1/2.5

R = 0.4

Hence, the proportion of days that are Rainy is 0.4

C = R

C = 0.4

Hence, the proportion of days that are Cloudy is 0.4

S = 0.5R

S = 0.5(0.4)

S = 0.2

Hence, the proportion of days that are Sunny is 0.2

8 0
3 years ago
A farmer sells 8.9 kilograms of apples and pears at the farmer's market. 3 /4 of this weight is apples, and the rest is pears. H
aleksandrvk [35]

Answer: 2.225 kg

Step-by-step explanation:

You know that:

- The total weight the farmer sold was 8.9 kilograms.

- 3/4 of this weight is apples, and the rest is pears.

Therefore, to calculate the amount of kilograms of pears   she sold at the farmer's market (which you can call x), you need to apply the following proccedure.

Thefore, you obtain the following result:

x=8.9kg-(8.9kg*\frac{3}{4})\\x=2.225kg

4 0
3 years ago
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Drag each tile to the correct box. A group of marine biologists on a marine expedition recorded the elevations at which they fou
yarga [219]

Answer:

Garden eel, Great white shark, sea urchin, Sea turtle

Step-by-step explanation:

Given that:

Animal ____ altitude

Sea turtle __ - 502

Sea urchin __ - 452

Garden eel __ - 396

Great white shark __ - 430

Arranging in decreasing order of elevation :

-396 > - 430 > - 452 > - 502

Hence, the animals can be arranged in decreasing order of elevation thus :

Garden eel, Great white shark, sea urchin, Sea turtle

4 0
3 years ago
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Komok [63]

Answer:  

I was not sure to what decimal point to round it to

a) Fraction: 2/7    Decimal: 0.28571   Percent: 28.571 %

b) Fraction: 5/7    Decimal: 0.71428   Percent: 71.428 %

c) Fraction: 1/7     Decimal: 0.14285   Percent: 14.285 %

7 0
3 years ago
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Hi guys can you please help me with this test.
Anika [276]
Sure! but unfortunately the picture is blank. not sure if it’s just my screen
4 0
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