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madreJ [45]
2 years ago
12

What are the similar features of Hinduism and Buddhism?

Biology
1 answer:
GalinKa [24]2 years ago
6 0

Answer:

Buddhism and Hinduism both originated in ancient India. Hinduism and Buddhism both involve belief in an ongoing process of rebirth. Both religions have same idea, that one may be released from ongoing rebirth, but are called different things and achieved through different actions.

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C. Pepsin is the hormone that is produced mainly in the stomach and regulates secretions of gastric juice.
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Sustainability of land use is involved in three parts. Which areas are these?
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1) full-cost pricing, (2) win-win solutions, and (3) a responsibility to future generations.

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Explain why a city that receives 10 hours more light each day has colder average temperatures.
goldenfox [79]

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Despite the hours of sunlight a city receives, the latitude of the city plays a larger role due to the fact that with a higher latitude, the higher the solar angle allowing a city to be much warmer.

Explanation:

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2 years ago
You are a botanist looking at the plant color in a new breed of Snapdragon. The two parent plants are Blue and Green and when yo
irakobra [83]

Answer:

Incomplete dominance is the inheritance pattern where the dominant allele did not mask the recessive allele completely and form a mix of both alleles. Here the inheritance is the incomplete inheritance. The ratio of F2 generation is 1:2:1.

Given:

R1R1 = 42

R2R2 = 39

R1R2 = 86

Total R1 alleles = 2*42+86 = 170

Total R2 alleles = 2*39+86 = 164

Total alleles = 334

Frequency of allele R1 = 170/334 = 0.51

Frequency of allele R2 = 164 / 334 = 0.49

Expected number of each phenotype:

Total population = 167

Blue = R1R1 = 0.51 * 0.51 * 167 = 43.44

Green = R2R2 = 0.49 * 0.49 * 167 = 40.10

Cyan = 2*R1*R2 = 2*0.51*0.49*167 = 83.46

Phenotype     Observed(O)    Expected (E)    O-E      (O-E)2     (O-E)2/E

Blue                 42                   43.44               -1.44       2.0736     0.0477

cyan                86                   83.46                 2.54     6.4516     0.0773

green              39                    40.1                    -1.1       1.2100      0.0302

Total              167                     167                                               0.1552

Chi-square value = 0.155

Degrees of freedom = no. of phenotypes – 1

Df = 3-1 = 2

Critical value = 5.99

Chi-square value of 0.155 is less than the critical value of 5.99. So we accept the null hypothesis.

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Which structure would you not find in a prokaryotic cell?
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