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alisha [4.7K]
3 years ago
8

HELP ASAP!! ILL GIVE BRAINLIEST

Mathematics
1 answer:
Luba_88 [7]3 years ago
3 0

Answer:

$23.86 I believe, im a bit rusty lol

Step-by-step explanation:

You might be interested in
the length of a rectangle is 5 times as long as its breadth and its area is 1620 m² find area of square whose perimeter is equal
Rus_ich [418]

Answer:

Area of the square is 2916 m^{2}.

Step-by-step explanation:

Let the breadth of the rectangle be represented by w. So that;

length of rectangle = 5w

Area of rectangle = length x breadth

                             = 5w x w

1620 = 5w^{2}

divide through by 5 to have,

w^{2} = 324

w = \sqrt{324}

   = 18

Thus, the breadth of the rectangle is 18 m.

length = 5 w = 5 x 18

           = 90 m

The length of the rectangle is 90 m.

Perimeter of the rectangle = 2(l + w)

                                  = 2( 90 + 18)

                                  = 216 m

Perimeter of a square = 4l

where l is the length of its side.

Given that the perimeters of the rectangle and square are equal, then;

4l = 216

l = \frac{216}{4}

 = 54

length of the side of square is 54 m.

Therefore,

Area of square = l^{2}

                         = 54^{2}

                        = 2916

Area of the square whose perimeter is equal to that of the rectangle is 2916 m^{2}.

6 0
3 years ago
A mining company estimates that the marginal cost of extracting x tons of copper ore from a mine is 0.6 + 0.008x, measured in th
Serhud [2]

Answer:

The cost of extracting the first 50 tons of copper is $151,000.

Step-by-step explanation:

Start-up costs of $150,000.

For the 50 tons of cooper.

C(x) = 0.6 + 0.008x

So

C(50) = 0.6 + 0.008*50 = 1

1 thousand dollars.

So

$150,000 + $1,000 = $151,000

The cost of extracting the first 50 tons of copper is $151,000.

8 0
2 years ago
Match each expression with the equivalent expression.
otez555 [7]
Hope this helps good luck

3 0
3 years ago
Solve for h in the figure below
kumpel [21]

Answer:

b. \frac{2}{3} \: ft

Step-by-step explanation:

\triangle ABE\sim \triangle CDE

(AA postulate)

\therefore \frac{AB}{CD} =\frac{BE}{DE}

\therefore \frac{2}{h} =\frac{24}{8}

\therefore \frac{2}{h} =3

\therefore h=  \frac{2}{3} \: ft

4 0
2 years ago
2,4,8,16 recursive form
AVprozaik [17]

Question

2,4,8,16 recursive form

Answer:

The first term is 2, and each  term after that is twice the previous term, so the equations are:

a sub1  = 2

a sub n = 2a sub n-1, for n>1

8 0
3 years ago
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