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alexandr402 [8]

2 years ago

5

Solve for h in the figure below

1 answer:

kumpel [21]2 years ago

4 0

Answer:

b. $\frac{2}{3} \: ft$

Step-by-step explanation:

$\triangle ABE\sim \triangle CDE$

(AA postulate)

$\therefore \frac{AB}{CD} =\frac{BE}{DE}$

$\therefore \frac{2}{h} =\frac{24}{8}$

$\therefore \frac{2}{h} =3$

$\therefore h= \frac{2}{3} \: ft$

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Answer:

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Step-by-step explanation:

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Rewrite (2x^2+13x+26) / x+4 in the form q(x)+r(x)/b(x) . Then find q(x) and r(x). In the rewritten expression, q(x) is_____and r

likoan [24]

The value of q(x) is $2 x+5$

The value of r(x) is $6$

Explanation:

The given expression is $\frac{2 x^{2}+13 x+26}{x+4}$

We need to rewrite the expression in the form of $q(x)+\frac{r(x)}{b(x)}$

Simplifying the expression, we get,

$\frac{2 x^{2}+8 x+5x+26}{x+4}$

Separating the fractions, we have,

$\frac{2 x^{2}+8 x}{x+4}+\frac{5 x+26}{x+4}$

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Now, we shall further simplify the term $\frac{5 x+26}{x+4}$ , we get,

$\frac{5 x+26}{x+4}=\frac{5 x+20}{x+4}+\frac{6}{x+4}$

Common out 5 from the numerator, we have,

$\frac{5 x+26}{x+4}=5+\frac{6}{x+4}$

Substituting the value $\frac{5 x+26}{x+4}=5+\frac{6}{x+4}$ in the equation(1), we get,

$2 x+5+\frac{6}{x+1}$

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$q(x)=2 x+5$

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Answer:

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Find the length of side x in simplest radical form with a rational denominator.

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Step-by-step explanation:

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