The answer comes after you evaluate the exponent, multiply, add, evaluate the square root, and multiply again
X= 1
X= -2
Answer:
134.5 degree
Step-by-step explanation:
first find the remaining side of a triangle
BY using cosine rule
C^2=A^2+B^2-2ABcosx
apply square root both sides
√c^2 =√[4^2+10^2-2(4)(10)cos29]
C=√(116-69.96958)
C=√46.03
C=6.8
Now find angle using cosine rule
C^2=A^2+B^2-2ABcosx
10^2=4^2+6.78^2-2(4)(6.78)cosx
100=16+45.9684-54.24cosx
100=61.9684-54.24cosx
100-61.9684=-54.24cosx
(38.0316)/-54.24=(-54.4cosx)/-54.24
-0.70117=cosx
X= cos inverse of -0.70117
x=134.5 degree
Answer:
F
Step-by-step explanation:
3(5) would be the equivalent of 3*5, adding the + n.
Answer:
348000
Step-by-step explanation:
The place you want to round to is the thousands place. The place to the right of that is the hundreds place. If the digit in the hundreds place is 5 or more (and it is), then the rounded number will have 1 added to its thousands digit.
After making that adjustment (if necessary), all digits to the right (hundreds, tens, ones, and so on) will be set to zero.
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<em>Comment on rounding</em>
Various rounding schemes are in use. The one described above is the one usually taught in school. In real life, it has the disadvantage that it can add a bias to a set of numbers, making their total come out higher than desired. In order to counter that, a "round to even" rule is sometimes used.
In this problem, that would mean the thousands digit would only be changed on the condition it would be changed to an even digit. (Here, that rule would give the same result. The number 346500 would be rounded down to 346000, for example.)
Various spreadsheets and computer programs implement different rounding schemes, depending on the application and the amount of bias that is tolerable. So, you may run across one that seems to be "wrong" according to what you learned in school.
Answer: yes this is a function
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The reason why is because we don't have any repeated x values. Each input (x) leads to exactly one output (y). If you plotted all the points, then you would not be able to pass a single vertical line through more than one point. So this graph passes the vertical line test.