Answer:
$80.15
Step-by-step explanation:
We can make an equation to solve this problem, that helps a lot. If h represented hours, we could make the equation 15.53h+s=157.8
Now we know that he worked 5 hours, so we can multiply 15.53 by 5 to simplify the equation.
15.53*5=77.65
So now the equation is 77.65+s=157.8.
Now, we can subtract 77.65 from both sides.
So now, our final equation is s=80.15
It cost $80.15 to buy supplies.
Hope this helps!
Answer: The option B. 1.9 is correct
Explanation:
We are given the below information:
x Probability P(x)
0 0.2
1 0.1
2 0.4
3 0.2
4 0.1
The expected value of x is given below:




Therefore, the expected value of x is 1.9
There are an infinite amount of prime numbers plz be more clear on the range
The answer would be a (not too sure) but it makes a little bit sense
Answer:

Step-by-step explanation:
<em>thinked</em><em> </em><em>number</em><em> </em><em>=</em><em> </em><em>x</em>
<em>multiply</em><em> </em><em>by</em><em> </em><em>3</em>
<em>
</em>
<em>add</em><em> </em><em>4</em><em> </em>
<em>
</em>
<em>square</em><em> </em><em>the</em><em> </em><em>result</em>
<em>
</em>
<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em>
<em>brainliest</em><em> </em><em>appreciated</em>
<em>good</em><em> </em><em>luck</em><em>!</em><em> </em><em>have</em><em> </em><em>a</em><em> </em><em>nice</em><em> </em><em>day</em><em>!</em>