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2 years ago

Can u solve this for me??

Mathematics

1 answer:

vekshin12 years ago

4 0

Answer:

75 weeks

Step-by-step explanation:

Let the number of weeks be x

10x + 45 = 789 Subtract 45 from both sides

10x = 789 - 45 Combine

10x = 744 Divide by 10

x = 744/10 Divide

x= 74.4 weeks. It will not hurt her to save the extra week to get the phone

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Find the quotient of -85^2-27n+76 / -17n-19

bagirrra123 [75]

Answer:
5n-4

Explanation:
The given expression is:
$\frac{-85n^2-27n+76}{-17n-19}$

1- Take the negative as a common factor from both the numerator and the denominator. This will give us:
$\frac{-(85n^2+27n-76)}{-(17n+19)}$

2- Cancel out the negative sign (common factor) from the numerator and denominator. This will give us:
$\frac{(85n^2+27n-76)}{(17n+19)}$

3- Factor the numerator. This wil give:
$\frac{(5n-4)(17n+19)}{(17n+19)}$

4- Finally, cancel out the (17n+19) which common in both numerator and denominator. This will give us the final expression:
5n-4

Hope this helps :)

6 0

2 years ago

Answer pls 3278+32+3213+89321+31398

goldenfox [79]

Answer:

oop

Step-by-step explanation:

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3 0

2 years ago

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What does 3/4 + 1/3 = quick answers i need to pass this

inn [45]

Answer:

1 1/12

Step-by-step explanation:

3/4 + 1/3

Get a common denominator of 12

3/4 * 3/3 = 9/12

1/3 * 4/4 =4/12

9/12 + 4/12

13/12

12/12 + 1/12

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6 0

2 years ago

find the x-intercepts and the coordinates of the vertex for the parabola Y equals negative X squared plus 8X -12. If there’s mor

Oksanka [162]

Answer:

x = 2, and 6

x = 2 , 6

Step-by-step explanation:

The quadratic function to analyze is: $y = -x^2+8x-12$

In order to find where the corresponding parabola intercepts the x axis, we set it equal to zero (y = 0):

$y = -x^2+8x-12\\0 = -x^2+8x-12\\x^2-8x+12=0$

This equation is easy to solve by factoring. We look for a air of integer numbers whose product equals the constant term "12", and whose combinig renders the coefficient of the middle term of the trinomial "-8".

The two such numbers are "-2" and "-6". We use them to split the middle term, and then solve by factoring by grouping:

$x^2-8x+12=0\\x^2-2x-6x+12=0\\(x^2-2x)+(-6x+12)=0\\x(x-2)-6(x-2)=0\\(x-2)(x-6)=0$

For the product of two factors to render zero, we need either one to be a zero.This means that (x-2)=0 (that is x = 2), or (x-6)=0 (that is x = 6).

So, there are two x-intercepts: x= 2, and 6

3 0

2 years ago

Whoever gets it right can have brainliest, but answer ASAP!

sdas [7]

Answer:

6.52

Step-by-step explanation:

6.52

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