The base of a logarithm should always be positive and can't be equal to 1, so the domain is 0 < <em>x</em> < 1 or <em>x</em> > 1.

Write both sides as powers of 1/<em>x</em> :

Recall that
, so that



Take the 5th root of both sides, recalling that 3⁵ = 243, so
![x=\sqrt[5]{\dfrac1{243}}=\boxed{\dfrac13}](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B5%5D%7B%5Cdfrac1%7B243%7D%7D%3D%5Cboxed%7B%5Cdfrac13%7D)
The answer is g=-10
Hope it helps
Answer:

Step-by-step explanation:
-(4x+6)<2(5x+9)+2x
Distribute:
-4x-6<10x+18+2x
Combine like terms on either side:
-4x-6<12x+18
We want to now gather variable terms on one side of the inequality and constants (terms without variables) on the opposing side.
Add 4x on both sides:
-6<16x+18
Subtract 18 on both sides:
-24<16x
Divide both sides by 16:
-24/16<x
This implies:
x>-24/16
Reduce:
x>-3/2
x>-1.5
So in an interval notation this is
.
Last time I checked that was about right, but it's been a few years since then.
Answer:
46lb
Step-by-step explanation:
you take twenty five divide by one twenty