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vova2212 [387]
2 years ago
6

He LSASAP don’t understand been stressing been waiting

Mathematics
1 answer:
Serggg [28]2 years ago
8 0

Answer:

f = 1.2

Step-by-step explanation:

locate x = - 6 on the x- axis, then go vertically up to meet the graph at (- 6, 1.2)

Then when x = - 6, f is 1.2

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Solve 5x - 8y = 11 for y.
disa [49]

Answer:

y = \frac{5x-11}{8}

Step-by-step explanation:

Given

5x - 8y = 11 ( subtract 5x from both sides )

- 8y = 11 - 5x ( multiply through by - 1 )

8y = - 11 + 5x = 5x - 11 ( divide both sides by 8 )

y = \frac{5x-11}{8}

3 0
3 years ago
Two vertices of a right triangle have coordinates (3, 7) and (3, 10) . The segment that connects these points is a leg of the tr
vesna_86 [32]
(7,8) I think is the answer your looking for
3 0
3 years ago
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A laptop has a listed price of $892.99 before tax. If the sales tax rate is 8.75%, find the total cost of the laptop wi the sale
Gnesinka [82]
Umm try googling it maybe I’m sorry
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2 years ago
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26. Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics
hjlf

The test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

<h3>What are null hypotheses and alternative hypotheses?</h3>

In null hypotheses, there is no relationship between the two phenomenons under the assumption or it is not associated with the group. And in alternative hypotheses, there is a relationship between the two chosen unknowns.

Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics course.

Then they are given a post-test once the professor has concluded lecturing on the material.

Pre-test and post-test scores for 4 students in an elementary statistics class are given below.

Then we have

\mu _d = \mu _{post} - \mu _{pre}

Then the null hypotheses and alternative hypotheses will be

H₀: \mu _d = 0

Hₐ: \mu _d > 0

Then the test statistic will be

\rm \overline{x} _d = \dfrac{\Sigma x_d}{n} = \dfrac{15+12+10+1}{4}\\\\\overline{x} _d = 9.5

Then

\rm S_d = 6.02

The test statistic value is given by

\rm t = \dfrac{\overline{x} _d }{\dfrac{S_d}{\sqrtn}} \\\\t = \dfrac{9.5}{\dfrac{6.02}{\sqrt4}}\\\\t = 3.16

Since this is a right-tailed test, so the critical value is given by

\rm t_{n-1}(\alpha ) = t_3 (0.05) = 2.353

Since the test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

Hence, we can conclude that \mu _d > 0 that is test scores have improved.

More about the null hypotheses and alternative hypotheses link is given below.

brainly.com/question/9504281

#SPJ1

7 0
2 years ago
Graph the line 2x – 3y = 12.
babunello [35]
Decided by 12 is 2 your welcome
8 0
2 years ago
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