1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Talja [164]
3 years ago
5

Can someone help me??

Mathematics
1 answer:
babymother [125]3 years ago
3 0

Answer:

y = \frac{1}{3} x + 8

Step-by-step explanation:

  • Find the slope: \frac{1}{3} ( parellel lines have the same slope)
  • Create an equation using the given ordered pair to find the

        y-intersept (b): 10 = \frac{1}{3} (6) + b

  • Reduce the numbers with the greatest common factor 3 : 10 = 2 + b
  • Move the variable to the left-hand side and change its sign : -b + 10 = 2
  • Calculate the diffrence : -x = -8
  • Change the signs on both sides of the equation: x = 8

Use the slope and y-itersept to creat the equation : y = \frac{1}{3} x + 8

You might be interested in
Expanding triple brackets, i will give brainliest
rewona [7]

Answer:

{x}^{3} + {x}^{2} −24x+36

Step-by-step explanation:

(x + 6)(x - 2)(x - 3)

[x(x−2)+6(x−2)](x−3)

( {x}^{2} −2x+6x−12)(x−3)

( {x}^{2} +4x−12)(x−3)

{x}^{3} + {x}^{2} −24x+36

<h3>Hope it is helpful....</h3>
4 0
3 years ago
What are period and amplitude for the function
sweet [91]

Answer: Period: 4. Amplitude: 3

Step-by-step explanation: The period is how long it takes for one cycle of the function (one up and down). In this graph, one cycle ends at 4.

The amplitude is how far away the extremes of the graph are from the midline. This graph is a total of 6 units tall, making the amplitude 3. (I usually find total graph height and divide by 2.)

5 0
3 years ago
Find the distance between the points (-4, -5 and (3, -1.
Komok [63]
<u><em>≡ We know that:</em></u>
⇔ (x_{1},y_{1}) → (-4,-5)
⇔ (x_{2},y_{2}) → (3,-1)

<u><em>≡ Solution:</em></u>
⇒ \sqrt{[(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}]}
⇒ \sqrt{[(3-(-4))^{2}+(-1-(-5))^{2}]}
⇒ \sqrt{[7^{2}+4^{2}]}
⇒ \sqrt{[49+16]}
⇒ \boxed{\sqrt{65}}
7 0
3 years ago
Read 2 more answers
What is the value of x in the equation 1/5x – 2/3y = 30, when y = 15?
lianna [129]

Answer:

x = 200

Step-by-step explanation:

1/5x – 2/3y = 30

substitute in y

1/5x - 2/3(15) = 30

multiply

1/5x - 10 = 30

isolate the variable

1/5x = 40

multiply each side by 5

x = 200

4 0
3 years ago
Read 2 more answers
I am a real number
Elden [556K]

Answer:Any number less than -13.

Step-by-step explanation:

If the number is real and rational and non-natural, this means that it can be any number in the negative number space.

Additionally, since the number has to be less than -13, then the number could be any number less than -13.

With all these things considered, the number is any number less than -13 that is real and rational.

Cheers.

5 0
3 years ago
Other questions:
  • Fiona is gathering signatures on a petition to save the Orangutans. If she gets 4 times the number of signatures that she has ri
    9·2 answers
  • A contractor wishes to build 9 houses, each different in design. In how many ways can he place these houses on a street if 6 lot
    8·2 answers
  • Need help with this question <br> factories 21x-14y
    8·2 answers
  • The area of a rectangular patio is 31 7/8 square meters. The width of the patio is 4 1/4 meters. What is the length? ( in simple
    14·2 answers
  • the perimeter of a rectangle is given by the formula p=2L+2Wwhete L is the lenght and W is width solve for L in the terms of P a
    13·2 answers
  • Find the slope between the two points.<br> (2,7) and (5, 8 )
    14·1 answer
  • A sample of 40 people owned an average of 1.35 hats. It is known from a previous study that the population standard deviation of
    5·1 answer
  • AT-Mobile advertises cut-rate phone service for $9.00 a
    11·1 answer
  • FIND THE AREA OF THE SHADED REGION.
    11·1 answer
  • Can someone help me with this? I'm confused
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!