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3 years ago

Please help will mark the brainliest

Mathematics

2 answers:

Anastaziya [24]3 years ago

8 0

Answer:

452.4 mi^2

Step-by-step explanation:

area of circle=πr^2

=22/7*(12)^2

=3.142*144

=452.448

=452.4 mi^2

jonny [76]3 years ago

7 0

Answer:

C) 452.4 mi²

Step-by-step explanation:

a = πr²

a = π * 12²

a = π * 144

a = 452.3893421169

a = 452.4

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mikes deli just sold 328 ham sandwiches this week. around how many ham sandwiches did mike sold every day this week?

Alenkasestr [34]

Answer:

46.9

Step-by-step explanation:

328/7 = 46.9

To double check: 46.9 x 7 = 328

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4 0

3 years ago

WhAt is the answer to -12 - 3=-51

svet-max [94.6K]

Greetings!

Simplify both sides of the equation.
$-12 - 3=-51$
$-15 \neq -51$

Both sides of the equation are not equal.

Hope this helps.
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7 0

4 years ago

A box contains 20 miniature golf putt-putt balls; 10 are

stellarik [79]

Answer: The answer is provided below

Step-by-step explanation:

From the question, a box contains 20 miniature golf putt-putt balls out of which 10 are yellow, 6 are red, and the remaining 4 are pink.

The probability of picking a red golf ball will be:

= 6/20 × 100

= 600/20

= 30%

If the red ball is replaced, the probability of picking a yellow golf ball will be:

= 10/20 × 100%

= 50%

5 0

3 years ago

A homeowner is fencing in his triangular

tia_tia [17]

Answer:

Step-by-step explanation:

Square root

5 0

4 years ago

The expected number of typographical errors on a page of a certain magazine is .2. What is the probability that an article of 10

Pavel [41]

Answer:

a) The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

Step-by-step explanation:

Given : The expected number of typographical errors on a page of a certain magazine is 0.2.

To find : What is the probability that an article of 10 pages contains

(a) 0 and (b) 2 or more typographical errors?

Solution :

Applying Poisson distribution,

$N\sim Pois(0.2)$

$P(N=r)=\frac{e^{-np}(np)^r}{r!}$

where, n is the number of words in a page

and p is the probability of every word with typographical errors.

Here, n=10 and E(N)=np=0.2

a) The probability that an article of 10 pages contains 0 typographical errors.

Substitute r=0 in formula,

$P(N=0)=\frac{e^{-0.2}(0.2)^0}{0!}$

$P(N=0)=\frac{e^{-0.2}}{1}$

$P(N=0)=e^{-0.2}$

$P(N=0)=0.8187$

The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors.

Substitute $r\geq 2$ in formula,

$P(N\geq 2)=1-P(N$

$P(N\geq 2)=1-[P(N=0)+P(N=1)]$

$P(N\geq 2)=1-[\frac{e^{-0.2}(0.2)^0}{0!}+\frac{e^{-0.2}(0.2)^1}{1!}]$

$P(N\geq 2)=1-[e^{-0.2}+e^{-0.2}(0.2)]$

$P(N\geq 2)=1-[0.8187+0.1637]$

$P(N\geq 2)=1-0.9825$

$P(N\geq 2)=0.0175$

The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

6 0

3 years ago