Answer:
Step-by-step explanation:
Does anyone know what the y-int is please help
2 answers:
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The first car consumed 40 gallons of gas and second car consumed 30 gallons of gas
<em><u>Solution:</u></em>
Let x = gallons consumed by car 1
Let y = gallons consumed by car 2
Fuel efficiency of car 1 = 15 miles per gallon
Distance covered in 1 gallon of gas = 15 miles
Fuel efficiency of car 2 = 25 miles per gallon
Distance covered in 1 gallon of gas = 25 miles
<em><u>Given a total gas consumption of 70 gallons</u></em>
Therefore,
gallons consumed by car 1 + gallons consumed by car 2 = 70
x + y = 70 ------ eqn 1
<em><u>The two cars went a combined total of 1350 miles</u></em>
Therefore,
gallons consumed by car 1 x distance covered in 1 gallon of gas of car 1 + gallons consumed by car 2 x distance covered in 1 gallon of gas of car 2 = 1350
15x + 25y = 1350 ----- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
From eqn 1,
x = 70 - y ------- eqn 3
<em><u>Substitute eqn 3 in eqn 2</u></em>
15(70 - y) + 25y = 1350
1050 - 15y + 25y = 1350
10y = 1350 - 1050
10y = 300
y = 30
<em><u>Substitute y = 30 in eqn 3</u></em>
x = 70 - 30
x = 40
Thus first car consumed 40 gallons of gas and second car consumed 30 gallons of gas
Answer:
0
Step-by-step explanation:
Substitute x = 3 into the rational expression
=
=
= 0