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Elena-2011 [213]
2 years ago
9

5x+4=-10x+19 Plis solo contesten los que saben

Mathematics
1 answer:
Readme [11.4K]2 years ago
8 0

Answer:

X = 3

Step-by-step explanation:

5x+4=-10x+19 \\ 4 - 19 =  - 10x - 5x \\  - 15 =  - 5x \\  - 5x =  - 15 \\ x =  \frac{ - 15}{ - 5}  \\ x = 3

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Will give brainliest worth 25 points
dezoksy [38]

Find the difference in temperature between each 1000 feet:

From 1 to 2: 30 - 23.5 = 6.5

From 2 to 3: 23.5 - 17 = 6.5

From 3 to 4: 17 - 10.5 = 6.5

The temperature change is constant as it drops 6.5 degrees for every 1000 foot gain in elevation.

At 5,000 feet the temperature would be : 10.5 - 6.5 = 4

At 6,000 feet: 4 - 6.5 = -2.5

At 7,000 feet: -2.5 - 6.5 = -9

At 8,000 feet: -9 - 6.5 = -15.5

At 8,000 feet the temperature would be  -15.5 degrees.

5 0
3 years ago
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Rewrite the equation by completing the square.<br> f(x) = x^2 - 2x + 17<br> f(x) = (x + |?|)^2 + |?|
Komok [63]

Answer:

f(X)= (x-1)²+16

Hope this helps

8 0
3 years ago
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sergejj [24]
6 x 6 which equals 36
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3 years ago
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The length of a rectangle is 24 units. Can the perimeter x of the rectangle be 60 units when its width y is 11 units? (1 point)
zlopas [31]
The first choice is correct. No, the rectangle cannot have x=60 and y=11 because x=48+2y.

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7 0
3 years ago
What is the probability that a randomly selected graduate has a job if he or she is attending college? Give your answer as
Andrej [43]

Complete question :

Suppose that of the 300 seniors who graduated from Schwarzchild High School last spring, some have jobs, some are attending college, and some are doing both. The following Venn diagram shows the number of graduates in each category. What is the probability that a randomly selected graduate has a job if he or she is attending college? Give your answer as a decimal precise to two decimal places.

What is the probability that a randomly selected graduate attends college if he or she has a job? Give your answer as a decimal precise to two decimal places.

Answer:

0.56 ; 0.60

Step-by-step explanation:

From The attached Venn diagram :

C = attend college ; J = has a job

P(C) = (35+45)/300 = 80/300 = 8/30

P(J) = (30+45)/300 = 75/300 = 0.25

P(C n J) = 45 /300 = 0.15

1.)

P(J | C) = P(C n J) / P(C)

P(J | C) = 0.15 / (8/30)

P(J | C) = 0.5625 = 0.56

2.)

P(C | J) = P(C n J) / P(J)

P(C | J) = 0.15 / (0.25)

P(C | J) = 0.6 = 0.60

5 0
2 years ago
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