Answer:
(-4)^12
Step-by-step explanation:
D 288 1/3 = 96/288 3/4 = 216/288 5/32 = 45/288 8/9 = 256/288
1/3 times 96 3/4 times 72 5/32 times 9 8/9 times 32
Hope This Helped! :3
Answer:
7/11 (Simplified Already)
Step-by-step explanation: 25÷2235=?
Dividing two fractions is the same as multiplying the first fraction by the reciprocal (inverse) of the second fraction.
Take the reciprocal of the second fraction by flipping the numerator and denominator and changing the operation to multiplication. Then the equation becomes
25×3522=?
For fraction multiplication, multiply the numerators and then multiply the denominators to get
2×355×22=70110
This fraction can be reduced by dividing both the numerator and denominator by the Greatest Common Factor of 70 and 110 using
GCF(70,110) = 10
70÷10110÷10=711
Therefore:
25÷2235=711
Solution by Formulas
Apply the fractions formula for division, to
25÷2235
and solve
2×355×22
=70110
Reduce by dividing both the numerator and denominator by the Greatest Common Factor GCF(70,110) = 10
70÷10110÷10=711
Therefore:
2/5÷22/35=7/11
Answer:
3⁸ or 6561
Step-by-step explanation:
First, let's look at PEMDAS - Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.
There are no parentheses, so let's solve the exponents.
3² • 9³
3² = 9
9³ = 729
Your expression is:
9 • 729
Now let's multiply.
= 6561
This number can also be expressed with exponents.
Since 9 = 3², 9³ = 3²⁽³⁾
Now your expression is:
3² • 3²⁽³⁾
First, solve the exponents by multiplying.
3² • 3⁶
When you multiply two expressions with exponents that have the same base (3), you add the exponents.
3² • 3⁶ = 3⁽²⁺⁶⁾ = 3⁸
3⁸ also equals 6561.
Your answer is 3⁸ or 6561.
Hope this helps!
Answer:
Find the midsegment of the triangle which is parallel to CA.
Tip
- A midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle.
- This segment has two special properties. It is always parallel to the third side, and the length of the midsegment is half the length of the third side.
- If two segments are congruent, then they have the same length or measure.In other words, congruent sides of a triangle have the same length.
We have to find the segment which is parallel to CA.
From the given data,
The segment EG is the midsegment of the triangle
ABC.
So we have,
A midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle. This segment has two special properties. It is always parallel to the third side.
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