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3 years ago

6

Needhdjdjdjdjdjdnhiskdjdjdjdjdjdjjshdjdjdjdjdjdjdjd

1 answer:

Lilit [14]3 years ago

5 0

9514 1404 393

Answer:

-(√2)/2

Step-by-step explanation:

The expression evaluated at n=a gives the indeterminate form 0/0, so L'Hopital's rule can be used to find the limit. The second expression comes from differentiating numerator and denominator. Then the form with n=a is no longer indeterminate.

$\displaystyle\lim_{n\to a}{\frac{\sqrt{2n}-\sqrt{3n-a}}{\sqrt{n}-\sqrt{a}}}=\lim_{n\to a}{\frac{\frac{2}{2\sqrt{2n}}-\frac{3}{2\sqrt{3n-a}}}{\frac{1}{2\sqrt{n}}-0}}\\\\=\sqrt{a}\left(\frac{2}{\sqrt{2a}}-\frac{3}{\sqrt{3a-a}}}\right)=\boxed{-\frac{1}{\sqrt{2}}}$

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The table below shows the ticket rates for whale watching trips offered by Beluga Fun Tours:

pav-90 [236]

Answer should be A.
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3 0

3 years ago

In any year, the weather can inflict storm damage to a home. From year to year, the damage is random. Let Y denote the dollar

krok68 [10]

Answer:

a. mean = 1000

standard deviation = 4358.9

b. expected value of average damage bar Y = 1000

probability bar y exceeds 2000 = 0.011

Step-by-step explanation:

we have p1 = 95%, y1 = 0, p2 = 5%, y2 = 20000

Mean = (0.95 * 0) + (0.05 * 20000)

= 1000

var(y) = E(y²) - E(Y)²

= we solve for E(y)²

= 0²*0.95 + 20000²*0.05

= 0 + 20000000

then the variance of y = 20000000 - 1000²

=20000000-1000000

= $19000000

standard deviation is the square root of variance

= √19000000

= 4358.9

2.

a. Expected value of average is also the mean = 1000

b. we are to find probability that barY exceeds 2000

$z=\frac{2000-1000}{\sqrt{19000000/100} }$

= 1000/435.889

= 2.29

1-p(z≤2.29)

= 1 - 0.989

= 0.011

so the probability that barY exceeds 2000 is 0.011

8 0

3 years ago

t hits the square dartboard shown below at a random point. Find the probability that the dart lands in the shaded circular regio

masha68 [24]

Given:

Required:

To find the probability that the dart land will be in the shaded region.

Explanation:

Area of the circle is given by the formula:

$A=\pi r^2$

Where r = radius

Thus the area of the circular region

$\begin{gathered} =(3.14)\times(2)^2 \\ =3.14\times4 \\ =12.56\text{ square in.} \end{gathered}$

The area of the square is given by the formula:

$=(side)^2$

Thus the area of the given square

$\begin{gathered} =(6)^2 \\ =36\text{ square in.} \end{gathered}$

The probability of an event is given by the formula:

$P=\frac{number\text{ of possible outcomes}}{Total\text{ number of outcomes}}$

The probability that the dart land will be in the shaded region

$=\frac{Area\text{ of the shaded region}}{Area\text{ of the square}}$

Thus probability

$\begin{gathered} P=\frac{12.56}{36} \\ P=0.3488 \\ P=0.349 \end{gathered}$

Final answer:

Thus the probability that the dart land will be in the shaded region is 0.349.

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dusya [7]

-- #34 is choice-C .

-- See the picture attached to this answer, for both solutions.

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3 years ago