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3 years ago

1/2x5/6, as a fraction, because my brain is not remembering rn

Mathematics

2 answers:

Vinvika [58]3 years ago

7 0

Answer:

5/12

Step-by-step explanation:

Pavel [41]3 years ago

4 0

5/12

you just multiply the numerators and the denominators

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14 times the difference of 8 and w

Lunna [17]

14(8-W)=0
(14*8)-(14*W)=0
112-14W=0
-112 -112
------------------- The answer is 8
-14W= -112
-14W/(-14)= -112/(-14)
W=8

5 0

3 years ago

$900,000 is what percent of $900,000?

USPshnik [31]

What type of question is this

8 0

3 years ago

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Maurinko [17]

Answer:

The slope is -3/4 and the y-intercept is 1.

Step-by-step explanation:

B is the point where the line cross the y-axis, or vertical axis. Slope is the steepness of the line. Determined by rise over run. When the slope goes down 3 units, the slope goes to the right 4 units.

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3 years ago

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SOMEONE PLEASE PLEASE HELP PLEASE HELP

mr Goodwill [35]

Answer:

see explanation

Step-by-step explanation:

Using the rule of exponents

$a^{m}$ = $\frac{1}{a^{-m} }$ , then

2 ÷ $10^{4}$ = 2 ÷ $\frac{1}{10^{-4} }$

To divide leave first, change ÷ to × , turn second upside down

= 2 × $10^{-4}$

6 0

3 years ago

Write the equation of the line that is perpendicular to 3x+2y=8 and goes through the point (-5,2)

kifflom [539]

Answer:

$\displaystyle y=\frac{2}{3}(x+5)+2$

Step-by-step explanation:

We need to find the equation of the line perpendicular to the line 3x+2y=8 and passes through (-5,2).

The given line can be expressed as:

$\displaystyle y=-\frac{3}{2}x+4$

We can see the slope of this line is m1=-3/2.

The slopes of two perpendicular lines, say m1 and m2, meet the condition:

$m_1.m_2=-1$

Solving for m2:

$\displaystyle m_2=-\frac{1}{m_1}$

$\displaystyle m_2=-\frac{1}{-\frac{3}{2}}$

$\displaystyle m_2=\frac{2}{3}$

Now we know the slope of the new line, we use the slope-point form of the line:

$y=m(x-h)+k$

Where m is the slope and (h,k) is the point. Using the provided point (-5,2):

$\boxed{\displaystyle y=\frac{2}{3}(x+5)+2}$

6 0

3 years ago