Since 1*7=7, 1 4/7= (7+4)/7=11/7. When dividing fractions, we switch the numerator and denominator for the bottom number, so in this case we'd have
(11/7)*(6/5)=66/35=around 1.89
Answer:
3>x
Step-by-step explanation:
2(4+2x)> 5x+5
8+4x > 5x +5
8-5> 5x - 4x
3>1x
\left[a _{3}\right] = \left[ \frac{ - b^{2}}{6}+\frac{\frac{ - b^{4}}{3}+\left( \frac{-1}{3}\,i \right) \,\sqrt{3}\,b^{4}}{2^{\frac{2}{3}}\,\sqrt[3]{\left( -1296 - 432\,b^{2} - 16\,b^{6}+\sqrt{\left( 1679616+1119744\,b^{2}+186624\,b^{4}+41472\,b^{6}+13824\,b^{8}\right) }\right) }}+\frac{\frac{ - \sqrt[3]{\left( -1296 - 432\,b^{2} - 16\,b^{6}+\sqrt{\left( 1679616+1119744\,b^{2}+186624\,b^{4}+41472\,b^{6}+13824\,b^{8}\right) }\right) }}{24}+\left( \frac{1}{24}\,i \right) \,\sqrt{3}\,\sqrt[3]{\left( -1296 - 432\,b^{2} - 16\,b^{6}+\sqrt{\left( 1679616+1119744\,b^{2}+186624\,b^{4}+41472\,b^{6}+13824\,b^{8}\right) }\right) }}{\sqrt[3]{2}}\right][a3]=⎣⎢⎢⎢⎢⎡6−b2+2323√(−1296−432b2−16b6+√(1679616+1119744b2+186624b4+41472b6+13824b8))3−b4+(3−1i)√3b4+3√224−3√(−1296−432b2−16b6+√(1679616+1119744b2+186624b4+41472b6+13824b8))+(241i)√33√(−1296−432b2−16b6+√(1679616+1119744b2+186624b4+41472b6+13824b8))⎦⎥⎥⎥⎥⎤
Answer:
Then g = 5.
Step-by-step explanation:
The only number that fits in g is 5.
2*5 - 4 = 6
So 2 x 5 = 10.
Which the equation is now 10 - 4 = 6.
So the answer is 5.
(3y+40)+(3x-70)=180
3y+3x-30=180
3y+3x=210
3(y+x)=210
y+x=70
x=70-y
meanwhile 180-120=x therefore x=60
therefore
60=70-y y=10
so x=60 y=10
