1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mash [69]
4 years ago
7

An unlit match contains approximately 1,000 J of chemical energy When it burns, the match releases

Chemistry
1 answer:
ololo11 [35]4 years ago
5 0

Answer:

350 J

Explanation:

The law of conservation of energy states that energy can neither be created nor destroyed but can only be converted from one form to another. This means that in a system, energy is not lost.

In this question, an unlit match contains approximately 1,000 J of chemical energy. When lit, thermal and light energy are emitted i.e. it gets converted to light and heat energy. If the thermal energy emitted was measured to be 400J, and the remaining match still contains 250J of chemical energy, then:

The amount of light energy emitted will be:

Total chemical energy (1000J) - {Remaining chemical energy (250J) + emitted thermal energy (400J)}

= 1000 - (400 + 250)

= 1000 - 650

= 350

Hence, the amount of light energy emitted is 350J

Note that, the amount of energy converted (thermal and light) and remaining chemical energy still equates the total chemical energy in the match.

You might be interested in
How to do moles in chemistry
zalisa [80]
1.) Write down the number of atoms that comprise each compound on either side of the equation. Using the chemical equation you can identify the atoms of each element in the reaction. Because a chemical reaction can never create or destroy new matter, a given equation is unbalanced if the number (and types) of atoms on each side of the equation don't perfectly match.Don’t forget to multiply through by a coefficient or subscript if one is present.

For example, H2SO4 + Fe ---> Fe2(SO4)3 + H2On the reactant (left) side of the equation there are 2 H, 1 S, 4 O, and 1 Fe.On the product (right) side of the equation there are 2H, 3 S, 12 O, and 2 Fe.
3 0
3 years ago
1.5 miles to centimeters ​
Gemiola [76]

hi

1 mile is  1 609 meters.  (rounded).

As there is 100 centimeters in a meter, then

1 mile is  160 900 centimeter.  

Then 1.5 miles , is 1 mile + one half so :

160 900 + 160 900 /2 =  160 900 + 80 450

                                     =  241 350

1.5 mile is  241 350  centimeters.  

please note that the value of a mile was rounded.

4 0
1 year ago
Read 2 more answers
Explain how the results of Ernest Rutherford’s gold–foil experiment showed that the atom is mostly empty space.
Katena32 [7]
He discovered this by firing Alpha particles at a gold foil and most alpha particles went through the foil and a few were deflected. The area where the alpha particles were deflected were assumed where the small dense positively charged nucleus was located. And electrons were scattered in the empty space out side the small nucleus.
Also be sure to check out my chemistry question 
4 0
3 years ago
Given the unbalanced equation below, answer the following: Calculate the number of liters of 3.00 M lead (II) iodide solution pr
mr_godi [17]

The number of liters of 3.00 M lead (II) iodide : 0.277 L

<h3>Further explanation</h3>

Reaction(balanced)

Pb(NO₃)₂(aq) + 2KI(aq) → 2KNO₃(aq) + PbI₂(s)

moles of KI = 1.66

From the equation, mol ratio of KI : PbI₂ = 2 : 1, so mol PbI₂ :

\tt \dfrac{1}{2}\times 1.66=0.83

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

\large \boxed {\bold {M ~ = ~ \dfrac {n} {V}}}

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

So the number of liters(V) of 3.00 M lead (II) iodide-PbI₂ (n=0.83, M=3):

\tt V=\dfrac{n}{M}\\\\V=\dfrac{0.83}{3}\\\\V=0.277~L

5 0
3 years ago
An insulated cup contains 66.0g of water at 22.00oC. A 28.50g sample of metal at 95.25oC is added. The final temperature of the
Vsevolod [243]

Answer:

Specific heat of metal of the metal is 0.8394J/g°C

Explanation:

The heat the water gain is the same losing for the metal. The equation is:

m(Metal)*ΔT(Metal)*S(Metal) = m(Water)*ΔT(Water)*S(Water)

<em>Where m is mass: 66.0g water and 28.5g Metal</em>

<em>ΔT is change in temperature: (95.25°C-27.84°C) = 67.41°C for the metal and (27.84°C - 22.00°C) = 5.84°C for the water</em>

<em>And S is specific heat of water (4.184J/g°C) and the metal</em>

<em />

Replacing:

28.5g*67.41°C*S(Metal) = 66.0g*5.84°C*4.184J/g°C

S(Metal) = 0.8394J/g°C

<h3>Specific heat of metal of the metal is 0.8394J/g°C</h3>

<em />

7 0
3 years ago
Other questions:
  • Please answer this attachment below
    14·1 answer
  • The element that has a valence configuration of 2s1 is ________.
    11·1 answer
  • Diamond and graphite are two crystalline forms of carbon. At 1 atm and 25∘C diamond changes to graphite so slowly that the entha
    10·1 answer
  • What is true about the number of water particles in the pot after the water has been warmed?
    14·1 answer
  • Consider this reaction occurring at 298 K: N2O(g) + NO2(g) 2 3 NO(g) a. Show that the reaction is not spontaneous under standard
    14·1 answer
  • Which chemical equation represents a redox reaction? A. Mg(ClO3)2 + 2HCl → MgCl2 + 2HClO3 B. CO + H2O → H2 + CO2 C. 2NH4NO3 + Cu
    9·2 answers
  • (Science)
    10·1 answer
  • The trade route that connected India to markets in Europe and the Arabian
    5·2 answers
  • Be sure to include the direction of the net force left or right
    7·1 answer
  • Of a 4 M solution of HCl, 1 L is diluted to 2M. What is the volume of the diluted solution?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!